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A particle of mass \(m\) makes an elastic head-on collision with a stationary particle of mass \(2 m .\) If initial kinetic energy is moving particle is \(6 J\), then during the impact, (1) the minimum kinetic energy of the system is \(2 f\) (2) the maximum elastic potential energy of the system is \(4 J\) (3) momentum and total energy are conserved at every instant (4) the ratio of kinetic energy to potential energy of the system first decreases and then increases

Short Answer

Expert verified
1. is false, 2. is true, 3. is true, 4. is true.

Step by step solution

01

Understand Conservation Laws

In any elastic collision, both momentum and kinetic energy are conserved. Since the collision involves two particles, we must set up equations to solve for these quantities. The moving particle is initially the only one with kinetic energy.
02

Initial Conditions

The initial kinetic energy of the moving particle is given as 6 J. The stationary particle has no kinetic energy initially. Therefore, the total initial kinetic energy of the system is 6 J.
03

Applying Conservation of Momentum

Conservation of momentum formula is: \[ mv = mv_1 + 2mv_2 \]Where \( v \) is the initial velocity of particle \( m \), and \( v_1 \) and \( v_2 \) are the final velocities of masses \( m \) and \( 2m \) respectively. Given the initial and final conditions, solve for these velocities.
04

Applying Conservation of Kinetic Energy

The conservation of kinetic energy formula is: \[ \frac{1}{2}mv^2 = \frac{1}{2}mv_1^2 + \frac{1}{2}(2m)v_2^2 \]Rewriting this using the given initial kinetic energy:\[ 6 J = \frac{1}{2}mv_1^2 + mv_2^2 \]From the conservation of momentum and kinetic energy, you will find \( v_1 = 0 \) and \( v_2 = \frac{\sqrt{6}}{2} \).
05

Calculate Maximum Elastic Potential Energy

During an elastic collision, the total kinetic energy at any instant is equal to the initial minus any potential energy stored at that instant. Therefore, at maximum compression, the kinetic energy will be temporarily converted into potential energy. Since kinetic energy conservation states 6 J = KE at final + PE at max, when KE is reduced to 2 J, PE becomes 4 J, not 4f.
06

Analyze Energy Transition

The ratio of kinetic energy to potential energy changes over time. Initially, all energy is kinetic; some portions are converted to potential energy during deformation, decreasing the ratio. After the collision, kinetic energy begins to increase again as potential energy is stored back as kinetic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
In the realm of elastic collisions, understanding momentum is key. Momentum refers to the quantity of motion an object has and is defined by the product of its mass and velocity. According to the law of conservation of momentum, the total momentum of an isolated system remains constant during a collision. This means that the total momentum before the collision is equal to the total momentum after the collision.

For the given exercise, consider two particles: a moving one with mass \( m \) and initial velocity \( v \), and a stationary one with mass \( 2m \). As expressed in the conservation of momentum formula:
  • Initial Momentum: \[ mv \]
  • Final Momentum: \[ mv_1 + 2m v_2 \]
The equation is \( mv = mv_1 + 2mv_2 \). In an elastic head-on collision, by using this equation alongside the conservation of kinetic energy, you can solve for the final velocities of both particles. This conservation law is crucial for determining how objects move post-collision.
Conservation of Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion, and in elastic collisions, it is also conserved. This means that the total kinetic energy of the system before and after the collision remains constant. To illustrate, let's delve into the given problem.

Initially, only the moving particle possesses kinetic energy, given as 6 J. During the collision, this energy will be redistributed between both particles. Applying the conservation of kinetic energy:
  • Initial Kinetic Energy: \[ \frac{1}{2}mv^2 = 6 \, J \]
  • Final Kinetic Energy: \[ \frac{1}{2}mv_1^2 + \frac{1}{2}(2m)v_2^2 \]
This relationship ensures that the sum of the kinetic energies after the collision equals the initial kinetic energy of the system. As calculated, the system confirms the velocities \( v_1 = 0 \) and \( v_2 = \frac{\sqrt{6}}{2} \), demonstrating how energy is transferred between the two particles while remaining conserved.
Potential Energy in Collisions
While kinetic energy is conserved in elastic collisions, potential energy can also play a crucial role during the event. Specifically, during the collision between particles, kinetic energy transforms temporarily into potential energy at the point of maximum compression.

During an elastic collision, the potential energy reaches its peak as the system's kinetic energy is at a minimum. Given the initial conditions, the exercise reveals a temporary conversion of kinetic energy to potential energy. The initial kinetic energy is 6 J, and at maximum compression, the kinetic energy reduces to 2 J. Therefore, the potential energy at this instant becomes 4 J, as calculated by the difference: 6 J - 2 J.

In elastic collisions, this back-and-forth transformation of energy between kinetic and potential forms enables the particles to regain their initial kinetic energies, underscoring the fundamental principles of energy conservation.

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