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A proton has mass1.710-27kg. What is the magnitude of the impulse required to increase its speed from 0.990c to 0.994c?

Short Answer

Expert verified

The magnitude of the impulse required to increase its speed from 0.990c to 0.994c is 2.00410-21Ns.

Step by step solution

01

Identification of the given data

  • The mass of a proton is 1.710-27kg.
  • The initial speed of a proton is 0.990c
  • The final speed of a proton is 0.994c
02

Definition of Impulse

m,尘补蝉蝉鈥刼蹿鈥则丑别鈥刾谤辞迟辞苍=1.710-27kgv,蹿颈苍补濒鈥剉别濒辞肠颈迟测=0.994c=0.9943108=2.982108鈥刴/蝉u,颈苍颈迟颈补濒鈥剉别濒辞肠颈迟测=0.990c=0.9903108=2.97108鈥刴/蝉

Impulse is the equivalent to the force as the change in momentum,

Impulse=mvmu(1)

Substitute these values in Equation (1),

localid="1657118294846" Impluse=1.6710-27鈥刱驳2.982108鈥刴/蝉1.6710-27鈥刱驳2.97108鈥刴/蝉=1.6710-272.9821081.6710-272.971081鈥刱驳1鈥刴1鈥剆=2.00410-21Ns

Hence,the magnitude of the impulse required to increase its speed from 0.990c to 0.994c is 2.00410-21Ns.

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