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A bowling ball is initially at rest. A Ping-Pong ball moving in the +z direction hits the bowling ball and bounces off it, traveling back in the –z direction. Consider a time interval ∆t extending from slightly before to slightly after the collision. (a) In this time interval, what is the sign of ∆Pz for the system consisting of both balls? (b) In this time interval, what is the sign of ∆Pz for the system consisting of the bowling ball alone?

Short Answer

Expert verified

a)∆Pz for the system consisting of both balls is zero.

b)∆Pzfor the system consisting of the bowling ball alone is positive

Step by step solution

01

Significance of conservation of momentum

The conservation of momentum is a fundamental rule of physics that asserts that when no external forces are acting on a system, its momentum remains constant.

02

The sign ∆Pz  for the system consisting of both balls

Part a)

∆Pz=0

Because there should be a conversion of momentum when the ping-pong ball bounces backward at a much higher velocity than the bowling ball travelling in the +z direction at a much slower velocity, and the overall momentum is considered only because the mass is more different

03

The sign ∆Pz for the system consisting of bowling ball alone

Part b)

∆Pz>0

The change in velocity for ping pong ball is greater as compare to the bowling ball.

Because having no momentum in the z-direction, that has some small positive momentum.

Momentum difference for bowling ball role="math" localid="1653980302269" =P2-P1=m2v2-m2v1

As v2<v1, the change will be negative.

Thus, the∆Pz for the system consist of bowling ball alone is negative.

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