91Ó°ÊÓ

Part a)

A bullet traveling at speed embeds in the wooden block. So we find the speed of a bullet, the speed of the wooden block after the bullet embeds. So, the system to analyze is bullet and wooden block.

Part b)

Statement: The total momentum before the collision equals the total momentum after the collision.

Mathematically representation can be written as,

$$\begin{gathered} P_i=P_f \\ {m}_1{m}_1+m_2{u}_2=m_1{v}_1+m_2{v}_2 \end{gathered}$$

Where $m_1{m}_2$are the mass of bodies,are$u_1{u}_2$ the speed of bodies before the collision, and$v_1{v}_2$ are the speed of bodies after the collision.

Statement 1)

After the collision, the speed of the block with thebullet stuck in it is the same as the speed of the bullet before the collision.

Where v is the final speed of the block with the bullet stuck in it.

Momentum before collision$P_i=m_1{u}_1$

Momentum after collision$P_f=\left(m_1+m_2\right)v=\left(m_1+m_2\right)u_1$

So the momentum of the system is

$P_i<P_f$

It does not follow the law of conservation of momentum.

Thus, the statement is false.

Statement 2)

The momentum of the block with the bullet stuck in it is the same as the momentum of the bullet before the collision.

$P_i=P_f$

It follows the law of conservation of momentum.

Thus, this statement is true.

Statement 3)

The initial momentum of the bullet is greater than the momentum of the block with the bullet stuck in it.

$P_i>P_f$

It does not follow the law of conservation of momentum.

Thus, this statement is false.