/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q41P Two balls of mass  are connecte... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Two balls of mass are connected by a low-mass spring (Figure 3.63). This device is thrown through the air with low speed, so air resistance is negligible. The motion is complicated: the balls whirl around each other, and at the same time the system vibrates, with continually changing stretch of the spring. At a particular instant, the ball has a velocity and the ball has a velocity. a) At this instant, what is the total momentum of the device? b) What is the net gravitational (vector) force exerted by the earth on the device? c) At a time later, what is the total momentum of the device?

Short Answer

Expert verified

a) the total momentum of the device is, b) the net gravitational (vector) force exerted by the earth on the device is and c) the total momentum of the device is

Step by step solution

01

Identification of the given data

The given data can be listed below as,

  • The mass of the first ball is

  • The mass of the second ball is

  • The first ball has a velocity of

  • The second ball has a velocity of

02

Significance of the momentum law for the device

The momentum law states that the amount of the momentum of a body remains constant that is the product of the mass and the velocity.

The equation of the momentum gives the momentum of the body. Moreover, the equation of force gives the net force on the device.

03

Determination of the momentum and the net force on the device

a) From the principle of conservation of the linear momentum, the momentum of the device is expressed as:

Here, P is the momentum of the particle, are the mass and the velocity of the first and the second particle respectively.

Substituting the values in the above equation, we get-

Thus, the total momentum of the device is .

b) From Newton’s gravitational law, the net gravitational force exerted by the earth on the object is expressed as:

Here, F is the net gravitational force, g is the acceleration due to gravity that isare the masses of the first and the second particle respectively.

Substituting the values in the above equation, we get-

Thus, the net gravitational (vector) force exerted by the earth on the device is

c) From the law of conservation of momentum, the equation of the total momentum of the device can be expressed as:

Here, p is the total momentum, F is the net gravitational (vector) force and t is the time required that is

Substituting the values in the above equation, we get-

Thus, the total momentum of the device is

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The mass of the earth is 6×1024 kg, the mass of the moon is7×1022 kg,, and the center-to-center distance is 4×108 m. How far from the center of the earth is the center of the mass of the Earth-Moon system? Note that the Earth’s radius is6.4×106 m.

Figure 3.61 shows two negatively charged objects (with the same charge) and one positively charged object. What is the direction of the net electric force on the positively charged object? If the net force is zero, state this explicitly.

Masses M and m attract each other with a gravitational force of magnitude F. Mass m is replaced with a mass 3 cm, and it is moved four times farther away. Now, what is the magnitude of the force?

The mass of Mars is 6.4×1023and its radius is 3.6×106 m. What is the value of constant g on Mars?

A planet of mass 4×1024 k²µ is at location〈5e11,−2e11,0〉 m. A star of mass 5×1050 k²µ is at location〈−2e11,3e11,0〉 m. It will be useful to draw a diagram of the situation, including the relevant vectors.

(a) What is the relative position vector pointing from the planet to the star?

(b) What is the distance between the planet and the star?

(c) What is the unit vector role="math" localid="1657099553132" r^in the direction of r^?

(d) What is the magnitude of the force exerted on the planet by the star?

(e) What is the magnitude of the force exerted on the star by the planet?

(f) What is the (vector) force exerted on the planet by the star?

(g) What is the (vector) force exerted on the star by the planet?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.