91Ó°ÊÓ

The given data can be listed below as,

• The mass of the earth is$6×{10}^{24} kg$.
• The mass of the Sun is$2×{10}^{30} kg$.
• The center-to-center distance of the earth and the Sun is role="math" localid="1658127083031" $1.5×{10}^{11}m$.

The law of the center of mass states that if a rigid object is pushed at its center of mass, then the object will always continue to move.

The equation of the position of the center of mass gives the distance of the center of mass of the Earth-Sun system.

From the law of the center of mass, the distance of the earth’s center to the Earth-Sun system is expressed as:

$r_{\text{dist}}=\frac{M_E{r}_E}{M_S+M_E}+\frac{M_s{r}_s}{M_S+M_E}$

Here, $r_{\text{dist}}$is the distance of the earth’s center to the Earth-Sun system, $M_S and M_E$are the mass of the sun and the earth respectively,$r_s and{r}_E$are the center to center distance of the sun and the earth and center to center distance of the earth that is 0.

Substituting the values in the above equation, we get-

$$\begin{gathered} r_{\text{dist}}=\frac{\left(2×{10}^{30}\mathrm{kg}\right)×\left(1.5×{10}^{11}\mathrm{m}\right)}{\left(6×{10}^{24}\mathrm{kg}\right)+\left(2×{10}^{30}\mathrm{kg}\right)} \\ {r}_{\text{dist}}=1.49×{10}^{-11}m \end{gathered}$$

Thus, the distance of the center of the Sun and the center of the mass of the Earth-Sun system is $1.49×{10}^{-11}m$