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It is not very difficult to accelerate an electron to a speed that is 99%of the speed of light, because the electron has such a very small mass. What is the ratio of the kinetic energy K to the rest energy mc2in this case? In the definition of what we mean by kinetic energy K, E=mc2+k, you must use the full relativistic expression for E, because v/c is not small compared to 1.

Short Answer

Expert verified

The ratio of kinetic energy and rest mass energy is 6.09:1.

Step by step solution

01

Identification of given data

The given data can be listed below,

  • Speed of electron is 99%of speed of light i.e., v=0.99c

02

Concept/Significance of rest mass.

Rest mass, also known as invariant mass, describes the fascinating behaviour of objects travelling at relativistic speeds. A massless particle possesses rest mass energy, which allows it to move.

03

Determination of the ratio of the kinetic energy K to the rest energy.

The kinetic energy of the particle is given by,

K.E=γmc2-mc2

Here, mc2is the rest mass energy of the particle and γis the relativistic factor whose value is,

γ=11-v/c2.

The value of γis given by,

γ=11-0.99c/c2=7.09

Substitute all values in the kinetic energy equation.

K.E=7.09mc2-mc2=6.09mc2

The ratio of kinetic energy with rest mass energy is given by,

K.Emc2=6.09mc2mc2=6.09:1

Thus, the ratio of kinetic energy and rest mass energy is 6.09:1.

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