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The mass of the satellite is $200\mathrm{kg}$

A satellite revolves around the earth and it requires energy. This is called as orbiting energy. As the satellite does revolve around the earth, the satellite get kinetic energy in a gravitational field and it gets potential energy.

The speed of a satellite,

$v=\sqrt{\frac{GM}{R}}鈰�鈰�\left(1\right)$

Where,

$G=6.6743脳{10}^{-11}\mathrm{N}路{\mathrm{m}}^2/{\mathrm{kg}}^2$

$M=200\mathrm{kg}$

$R=\text{Radius of the earth}=6371000\mathrm{m}$

Substitute these values in Equation (1),

$v=\sqrt{\frac{GM}{R}}$

$=\sqrt{\frac{6.6743脳{10}^{-11}脳200}{6371000}路\left(\frac{\left(1\mathrm{N}路{\mathrm{m}}^2/{\mathrm{kg}}^2\right)脳1\mathrm{kg}}{1\mathrm{m}}\right)}$

$=\sqrt{\frac{6.6743脳{10}^{-11}脳200}{6371000}路\left(\frac{(1\mathrm{N}路\mathrm{m})}{\mathrm{kg}}脳\frac{1\mathrm{kg}路\mathrm{m}/{\mathrm{s}}^2}{1\mathrm{N}}\right)}$

$=\sqrt{\frac{6.6743脳{10}^{-11}脳200}{6371000}路\left(1{\mathrm{m}}^2/{\mathrm{s}}^2\right)}$

Hence, the speed of a satellite in a circular orbit near the Earth is $4.58脳{10}^{-8}\mathrm{m}/\mathrm{s}$

Total Energy = Kinetic Energy + Potential Energy

$\text{TE KE + PE}$

$\frac{GMm}{2r}-\frac{GMm}{r}$

$=-\frac{GMm}{2r}$

Substitute these values in above expression,

$TE=-\frac{6.6743脳{10}^{-11}\left(\mathrm{N}路{\mathrm{m}}^2/{\mathrm{kg}}^2\right)脳5.972(\mathrm{kg})脳{10}^4脳200(\mathrm{kg})}{2脳6371000\mathrm{m}}$

$=-6.26脳{10}^{-11}路\left(\frac{\left(\frac{1\mathrm{N}路{\mathrm{m}}^2}{\mathrm{kg}}\right)脳(1\mathrm{kg})脳(1\mathrm{kg})}{1\mathrm{m}}\right)$

$=-6.26脳{10}^{-11}路\left(1\mathrm{N}路\mathrm{m}脳\frac{1\mathrm{J}}{1\mathrm{N}路\mathrm{m}}\right)$

$=-6.26脳{10}^{-11}\mathrm{J}$

The total energy of the satellite is negative which means a satellite will never be able to escape from the gravitational pull of the Earth.