91影视

The value of nucleus mass = $3.499612脳{10}^{-25}kg$

The value of He-4 nucleus mass = $6.640678脳{10}^{-27}kg$

The value of a new nucleus mass = $3.433132脳{10}^{-25}kg$

The expression of the mass difference between alpha particle and new nucleus is expressed as follows:

$m=Nucleusmass-\left[He-4nucleusmass+newnucleusmass\right]$

Here, represents the mass difference between alpha particle and new nucleus.

Substitute all the known values in the above expression.

$$\begin{gathered} m=\left(3.499612脳{10}^{-25}kg\right)-\left[\left(6.640678脳{10}^{-27}kg\right)+\left(3.433132脳{10}^{-25}\right)\right] \\ =7.322脳{10}^{-30}kg \end{gathered}$$

The expression of the combined kinetic energy of the alpha particle and the new nucleus is expressed as follows:

$E=m{c}^2$

Here, $E$ represents the combined kinetic energy of the alpha particle and the new nucleus and $C$ represents the speed of light in vacuum whose value is$c=3脳{10}^{8}m/s$ .

Substitute all the known values in the above expression.

$$\begin{gathered} E=\left(7.322脳{10}^{-30}\right){\left(3脳{10}^{8}m/s\right)}^2 \\ =6.5898脳{10}^{13}kg{m}^2|s^2 \\ =\left(6.5898脳{10}^{-13}kg{m}^2|s^2\right)脳\left(\frac{1J}{1kg{m}^2|s^2}\right) \\ =6.5898脳{10}^{-130}J \end{gathered}$$

Thus,the combined kinetic energy of the alpha particle and new nucleus is$6.5898脳{10}^{-13}J$ .

The relation between electron-volt and joule is expressed as follows:

$1eV=1.6脳{10}^{-13}J$

The combined kinetic energy of alpha particle and the new nucleus in terms of electron-volt unit can be calculated as,

$E=6.5898脳{10}^{-13}J$

role="math" localid="1654102911061" $$\begin{gathered} =\left(6.5898脳{10}^{-13}J\right)\left(\frac{{\displaystyle \frac{1}{1.6脳{10}^{-19}}}eV}{1J}\right) \\ =4.1186脳{10}^{5}eV \end{gathered}$$

Thus, the combined kinetic energy of alpha particle and the new nucleus in terms of electron-volt unit is$4.1186脳{10}^{5}eV$ .