91影视

The free energy principle defines how non-equilibrium steady-states are maintained in living and non-living systems by restricting their states to a minimal number. It establishes that systems minimise a free energy function of their internal states, implying hidden states in the environment.

Use the definition of thermal energy in order to obtain the change of energy in the water $\text{螖}{\mathrm{E}}_{\text{thermal}}$.

$\begin{array}{c}{\mathrm{螖贰}}_{\text{thermal}}={\left(\mathrm{尘颁螖罢}\right)}_{\text{H2O}}\\ =\left(\text{500g}\right)\left(\text{4.2}\frac{\text{J}}{{\text{g}}^{\text{o}}\text{C}}\right)\left({\text{80}}^{\text{o}}{\text{C-20}}^{\text{o}}\text{C}\right)\\ ={\text{1.26脳10}}^{\text{5}}\text{J}\end{array}$

Therefore, the change in energy of water is obtained as $\text{螖}{\mathrm{E}}_{\text{thermal}}{\text{=1.26脳10}}^5\text{J}$.

According to the energy principle, this change of energy in the water is equal to the input of heat and work. Write this into an equation, in which then proceed to solve for the heat $\mathrm{Q}$.

${\mathrm{螖贰}}_{\mathrm{thermal}}=\mathrm{Q}+\mathrm{W}$

Solve for$\mathrm{Q}$ and substitute the values,

$\begin{array}{c}\mathrm{Q}={\mathrm{螖贰}}_{\mathrm{thermal}}-\mathrm{W}\\ {\text{=1.26脳10}}^{\text{5}}{\text{闯-5脳10}}^{\text{4}}\text{J}\\ {\text{=7.6脳10}}^{\text{4}}\text{J}\end{array}$

Therefore, the equation of heat is obtained as$\text{Q}={\text{7.6脳10}}^{\text{4}}\text{J}$ .

The energy gained by the mass of water is equal to the energy loss of the surroundings by considering the surroundings as everything but the mass of water.

Hence, the electric beater is also part of the surroundings.

Write the relation between energy of surrounding and thermal energy.

$\begin{array}{c}{\mathrm{螖贰}}_{\text{surroundings}}=鈭�{\mathrm{螖贰}}_{\text{thermal}}\\ =鈭�{\text{1.26脳10}}^{\text{5}}\text{J}\end{array}$

Therefore, energy change in the surroundings is obtained as$鈭�{\text{1.26脳10}}^{\text{5}}\text{J}$ .