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Chapter 16: Q33P (page 663)

Locations A and B are in a region of uniform electric field, as shown in Figure 16.67. Along a path from B to A, the change in potential is-2200V. The distance from A to B is 0.28m. What is the magnitude of the electric field in this region?

Short Answer

Expert verified

The magnitude of the electric field is7857.143N/C

Step by step solution

01

Change in the electric potential energy

The magnitude of the electric field for a charged particle (positive or negative) relies on the change in the electric potential energy of that particle.

Also, the potential energy change with the amount of distance the particle travels in the electric filed.

02

Given data

The change in the potential from B to A is,螖痴BA=-2200鈥�V. .

The distance from A to B is, 螖濒AB=0.28鈥�m.

03

The magnitude of the electric field

Theformula for the magnitude of the electric field in the regionis given by,

螖痴BA=-E脳螖滨ABE=螖痴BA螖滨ABE=--2200鈥�V0.28m脳1N/C1V/mE=7857.143N/C

Hence, the magnitude of the electric field is 7857.143鈥�N/C.

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Most popular questions from this chapter

15,000VIn the cathode ray tube found in old television sets, which contains a vacuum, electrons are boiled out of a very hot metal filament placed near a negative metal plate. These electrons start out nearly at rest and are accelerated toward a positive metal plate. They pass through a hole in the positive plate on their way toward the picture screen, as shown in the diagram in Figure 16.69. If the high-voltage supply in the television set maintains a potential difference of 15,000Vbetween the two plates, what speed do the electrons reach?

An electron is initially at rest. It is moved from a location 4脳10-10mfrom a proton to a location 6脳10-10m from the proton. What is the change in electric potential energy of the system of proton and electron?

A dipole is oriented along the x axis. The dipole moment is p=(qs).

(a) Calculate exactly the potential V(relative to infinity) at a location {x,0,0}on the xaxis and at a location {0,y,0}on the yaxis, by superposition of the individual 1/rcontributions to the potential.

(b) What are the approximate values of Vat the locations in part (a) if these locations are far from the dipole?

(c) Using the approximate results of part (b), calculate the gradient of the potential along the xaxis, and show that the negative gradient is equal to the x component Ex of the electric field.

(d) Along the y axis, dV/dy=0. Why isn鈥檛 this equal to the magnitude of the electric field Ealong the yaxis?

Question: If the kinetic energy of an electron is 4.4脳10-18J, what is the speed of the electron? You can use the approximate (non relativistic) equation here.

For a path starting at B and going to A (Figure 16.9), calculate (a) the change in electric potential, (b) the potential energy change for the system when a proton moves from B to A, and (c) the potential energy change for the system when an electron moves from B to A. For a path starting at B and going to C, calculate (d) the change in electric potential, (e) the potential energy change for the system when a proton moves from B to C, and (f) the potential energy change for the system when an electron moves from B to C.
See all solutions

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