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Locations A and B are in a region of uniform electric field, as shown in Figure 16.67. Along a path from B to A, the change in potential is-2200V. The distance from A to B is 0.28m. What is the magnitude of the electric field in this region?

Short Answer

Expert verified

The magnitude of the electric field is7857.143N/C

Step by step solution

01

Change in the electric potential energy

The magnitude of the electric field for a charged particle (positive or negative) relies on the change in the electric potential energy of that particle.

Also, the potential energy change with the amount of distance the particle travels in the electric filed.

02

Given data

The change in the potential from B to A is,Δ³ÕBA=-2200 V. .

The distance from A to B is, Δ±ôAB=0.28 m.

03

The magnitude of the electric field

Theformula for the magnitude of the electric field in the regionis given by,

Δ³ÕBA=-E×Δ±õABE=Δ³ÕBAΔ±õABE=--2200 V0.28m×1N/C1V/mE=7857.143N/C

Hence, the magnitude of the electric field is 7857.143 N/C.

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