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The mobility of Na+ions in water is5.2×10-8(m/s)(N/C). If an electric field of2400N/Cis maintained in the fluid, what is the drift speed of the sodium ions?

Short Answer

Expert verified

The drift speed of the sodium ions is 1.25×10-4m/s.

Step by step solution

01

Identification of the given data

The given data is listed below as,

  • The mobility of theNa+ ion in water is,μ=5.2×10-8m/s/N/C
  • The electric field maintained in the fluid is,E=2500N/C
02

Significance of the drift velocity

The drift velocity refers to the average velocity a charged particle attains due to the involvement of an electric field.

The equation of the drift velocity gives the drift speed of the sodium ions.

03

Determination of the drift speed of the sodium ion

The equation of the drift speed of the sodium ion is expressed as,

v=μE

Here, μis the mobility of the sodium ion andEis the electric field.

Substitute all the values in the above expression.

v=5.2×10-8m/sN/C×2400N/C=1.25×10-4m/s

Thus, the drift speed of the sodium ions is 1.25×10-4m/s.

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Most popular questions from this chapter

A neutral copper block is polarized as shown in Figure 14.90, due to an electric field made by external charges (not shown). Which arrow (a–j) in Figure 14.90 best indicates the direction of the net electric field at location B, which is inside the copper block ?

A negatively charged iron block is placed in a region where there is an electric field downward (in the Y − direction) due to charges not shown. Which of the diagrams (a–f) in Figure 14.88 best describes the charge distribution in and/or on the iron block?

If the distance between a neutral atom and a point charge is doubled, by what factor does the force on the atom by the point charge change?

(a)The positively charged particle shown in diagram 1 in Figure 14.94 creates an electric field \({{\bf{\vec E}}_{\bf{p}}}\) at location A. Which of the arrows (a–j) in Figure 14.94 best indicates the direction of \({{\bf{\vec E}}_{\bf{p}}}\) at location A?

(b)Now a block of metal is placed in the location shown in diagram 2 in Figure 14.94. Which of the arrows (a–j) in Figure 14.94 best indicates the direction of the electric field \({{\bf{\vec E}}_{\bf{m}}}\) at location Adue only to the charges in and/or on the metal block?

(c)\(\left| {{{{\bf{\vec E}}}_{\bf{p}}}} \right|\)is greater than \(\left| {{{{\bf{\vec E}}}_{\bf{m}}}} \right|\). With the metal block still in place, which of the arrows (a–j) in Figure 14.94 best indicates the direction of the net electric field at location A?

(d)With the metal block still in place, which of the following statements about the magnitude of \({{\bf{\vec E}}_{\bf{p}}}\), the field due only to the charged particle, is correct?

(1) \(\left| {{{{\bf{\vec E}}}_{\bf{p}}}} \right|\)is less than it was originally, because the block is in the way.

(2) \(\left| {{{{\bf{\vec E}}}_{\bf{p}}}} \right|\)is the same as it was originally, without the block.

(3) \(\left| {{{{\bf{\vec E}}}_{\bf{p}}}} \right|\)is zero, because the electric field due to the particle can’t go through the block.

(e)With the metal block still in place, how does the magnitude of\({{\bf{\vec E}}_{{\bf{net}}}}\) at location Acompare to the magnitude of \({{\bf{\vec E}}_{\bf{p}}}\)?

(f)Which of the arrows (a–j) in Figure 14.94 best indicates the direction of the net electric field at the center of the metal block (inside the metal)?

If the distance between a neutral atom and a point charge is tripled, by what factor does the force on the atom by the point charge change? Express your answer as a ratio: new force/original force.

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