91Ó°ÊÓ

The given data is listed below as:

• The ring’s charge is, Q

• The charge of the one single piece of the ring is, $\mathbf{∆}\mathit{Q}$

• The angle created by the ring’s one piece is, $\mathbf{∆}\mathit{θ}$

• The one piece’s arc length is, $\mathbf{∆}\mathit{r}$

The electric field is independent on the test charge amount and it is described as the property of the system of various charges. The electric field also gives direction and magnitude of a particular electric force.

For a particular charged ring, the product of the length of the ring’s piece and charge’s linear density gives the charge of one single piece of a ring. As there is uniform distribution of charges, the linear density of the ring is described as the division of the total charge and the ring’s total length.

The length of one single piece of a ring is described as the length of a particular arc that is subtended by a particular angle $\mathbf{∆}\mathit{θ}$which eventually becomes $\mathit{r}\mathbf{∆}\mathit{θ}$.

The equation of the charge of the ring is expressed as:

$\mathbf{∆}\mathit{Q}\mathbf{=}\frac{\mathbf{Q}}{\mathbf{L}}\mathbf{(}\mathbf{∆}\mathbf{r}\mathbf{)}$

Here, $\mathit{Q}$is the entire ring’s charge, $\mathit{L}$is the ring’s length and $\mathbf{∆}\mathit{r}$is the length of one ring’s piece.

Substitute $\mathit{r}\mathbf{∆}\mathit{θ}$for $\mathbf{∆}\mathit{r}$and role="math" localid="1657172632070" $\mathbf{2}\mathit{π}\mathit{r}$for $\mathit{L}$in the above equation.

$$\begin{gathered} \mathbf{∆}\mathit{Q}\mathbf{=}\frac{\mathbf{Q}}{\mathbf{2}\mathbf{Ï€°ù}}\mathbf{(}\mathbf{r}\mathbf{∆}\mathbf{θ}\mathbf{)} \\ \mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{}\mathbf{=}\frac{\mathbf{Q}}{\mathbf{2}\mathbf{Ï€}}\mathbf{(}\mathbf{∆}\mathbf{θ}\mathbf{)} \end{gathered}$$

Thus, the value of $\mathbf{∆}\mathit{Q}$is $\frac{\mathbf{Q}}{\mathbf{2}\mathbf{π}}\mathbf{(}\mathbf{∆}\mathbf{θ}\mathbf{)}$.

The integration variable is the angle $\mathit{θ}$. Hence, because of summing up all ring’s parts, the integration limits for the angle $\mathit{θ}$is $\mathbf{0}$to $\mathbf{2}\mathit{π}$.

Thus, the integration limits are $\mathbf{0}$to $\mathbf{2}\mathit{Ï€}$.