/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q1Q Under what conditions is the mom... [FREE SOLUTION] | 91影视

91影视

Under what conditions is the momentum of a system constant? Can the x component of momentum be constant even if the y component is changing? In what circumstances? Give an example of such behavior.

Short Answer

Expert verified

The momentum of a system is constant if there is no net vector force on the system.

Yes,the xcomponent of momentum be constant even if they component is changing if the object is moving in xz plane.

Step by step solution

01

Significance of the momentum of a system

Momentum is defined as the product of the mass and velocity of the object and it can be changed by applying the force to the object. So, it can be constant if no external force acts on the system.

02

Identification of the condition of the constant momentum of a system

In the case when net vector forces are not acting on the system, then the momentum is said to be constant.

Assume that a ball is moving in xz plane. In this condition, gravitational force and centripetal force will act in y direction only that will result in the change in the y component of the momentum. There will not be any force that will act in x direction , so there is no change in the x component of the momentum.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two asteroids in outer space collide and stick together. The mass of each asteroid, and the velocity of each asteroid before the impact, are known. To find the momentum of the stuck-together asteroids after the impact, what approach would be useful? (1) Use the Energy Principle. (2) Use the Momentum Principle. (3) It depends on whether or not the speed of the asteroids was near the speed of light. (4) Use the relationship among velocity, displacement, and time. (5) It depends on whether the collision was elastic or inelastic.

There is an unstable particle called the 鈥渟igma-minus鈥 (), which can decay into a neutron and a negative pion (蟿蟿):-n+蟿蟿-. The mass of the -is 1196MeV/c2, the mass of the neutron is 939 MeV/c2, and the mass of the 蟿蟿is 140MeV/c2. Write equations that could be used to calculate the momentum and energy of the neutron and the pion. You do not need to solve the equations, which would involve some messy algebra. However, be clear in showing that you have enough equations that you could in principle solve for the unknown quantities in your equations. It is advantageous to write the equations not in terms of v but rather in terms of E and p; remember that E2-(c)2=(mc2)2.

Redo the analysis of the Rutherford experiment, this time using the concept of the centre-of-momentum reference frame. Let m = the mass of the alpha particle and M = the mass of the gold nucleus. Consider the specific case of the alpha particle rebounding straight back. The incoming alpha particle has a momentum p1 , the outgoing alpha particle has a momentum p3 , and the gold nucleus picks up a momentum p4 . (a) Determine the velocity of the centre of momentum of the system. (b) Transform the initial momenta to that frame (by subtracting the centre-of-momentum velocity from the original velocities). (c) Show that if the momenta in the centre-of-momentum frame simply turn around (180鈼), with no change in their magnitudes, both momentum and energy conservation are satisfied, whereas no other possibilitysatisfies both conservation principles. (Try drawing some other
momentum diagrams.) (d) After the collision, transform back to
the original reference frame (by adding the center-of-momentum
velocity to the velocities of the particles in the center-of-mass
frame). Although using the center-of-momentum frame may be
conceptually more difficult, the algebra for solving for the final
speeds is much simpler

A uranium atom traveling at speed4104m/scollides elastically with a stationary hydrogen molecule, head-on. What is the approximate final speed of the hydrogen molecule?

Give an example of what we can learn about matter through the use of momentum and energy conservation applied to scattering experiments. Explain what it is that we cannot learn this way, for which we need to measure the distribution of scattering angles.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.