Chapter 6: Problem 3
By sketching a graph of \(y=3 x-1\) show that this is a one-to-one function.
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Chapter 6: Problem 3
By sketching a graph of \(y=3 x-1\) show that this is a one-to-one function.
These are the key concepts you need to understand to accurately answer the question.
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Calculate \(f(x+h)\) when (a) \(f(x)=x^{2}\) (b) \(f(x)=x^{3}\) (c) \(f(x)=\frac{1}{x}\) In each case write down the corresponding expression for \(f(x+h)-f(x)\).
If \(f(x)=x+6\) and \(g(x)=x^{2}-5\) find (a) \(f(g(0))\), (b) \(g(f(0))\), (c) \(g(g(2))\), (d) \(f(g(7))\).
Draw a graph of the function $$ f(x)= \begin{cases}2 x+1 & x<3 \\ 5 & x=3 \\ 6 & x>3\end{cases} $$ Find (a) \(\lim _{x \rightarrow 0^{+}} f(x)\) (b) \(\lim _{x \rightarrow 0}-f(x)\) (c) \(\lim _{x \rightarrow 0} f(x)\) (d) \(\lim _{x \rightarrow 3^{+}} f(x)\) (e) \(\lim _{x \rightarrow 3^{-}} f(x)\) (f) \(\lim _{x \rightarrow 3} f(x)\)
Study graphs of \(y=3 x-2\) and \(y=-7 x+1\). Are these continuous functions?
Plot a graph of the following functions. In each case state the domain and the range of the function. (a) \(f(x)=3 x+2,-2 \leq x \leq 5\) (b) \(g(x)=x^{2}+4,-2 \leq x \leq 3\) (c) \(p(t)=2 t^{2}+8,-2 \leq t \leq 4\) (d) \(f(t)=6-t^{2}, 1 \leq t \leq 5\)
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