Chapter 6: Problem 3
If \(f(x)=x+6\) and \(g(x)=x^{2}-5\) find (a) \(f(g(0))\), (b) \(g(f(0))\), (c) \(g(g(2))\), (d) \(f(g(7))\).
Short Answer
Expert verified
In summary, we found the following compositions at the given specific values:
a) \(f(g(0)) = 1\)
b) \(g(f(0)) = 31\)
c) \(g(g(2)) = -4\)
d) \(f(g(7)) = 50\)
Step by step solution
01
Calculate g(0)
Substitute 0 into the function g(x):
\(g(0) = (0)^2 - 5 = -5\)
02
Calculate f(g(0))
Now substitute the value of g(0) into the function f(x):
\(f(g(0)) = f(-5) = (-5) + 6 = 1\)
So, \(f(g(0)) = 1\).
#b) g(f(0))#
03
Calculate f(0)
Substitute 0 into the function f(x):
\(f(0) = (0) + 6 = 6\)
04
Calculate g(f(0))
Now substitute the value of f(0) into the function g(x):
\(g(f(0)) = g(6) = (6)^2 - 5 = 36 - 5 = 31\)
So, \(g(f(0)) = 31\).
#c) g(g(2))#
05
Calculate g(2)
Substitute 2 into the function g(x):
\(g(2) = (2)^2 - 5 = 4 - 5 = -1\)
06
Calculate g(g(2))
Now substitute the value of g(2) into the function g(x) again:
\(g(g(2)) = g(-1) = (-1)^2 - 5 = 1 - 5 = -4\)
So, \(g(g(2)) = -4\).
#d) f(g(7))#
07
Calculate g(7)
Substitute 7 into the function g(x):
\(g(7) = (7)^2 - 5 = 49 - 5 = 44\)
08
Calculate f(g(7))
Now substitute the value of g(7) into the function f(x):
\(f(g(7)) = f(44) = (44) + 6 = 50\)
So, \(f(g(7)) = 50\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Evaluation
Function evaluation refers to the process of determining the output of a function when a specific input is substituted into it. This is a fundamental concept in mathematics, as it allows us to understand how functions behave for different input values. In our exercise, we have two functions: a linear function, \(f(x) = x + 6\), and a quadratic function, \(g(x) = x^2 - 5\). To find values like \(f(g(0))\), \(g(f(0))\), \(g(g(2))\), and \(f(g(7))\), we must first evaluate the inner function with a given input and then use that result as the input for the outer function.
For example, to find \(f(g(0))\):
For example, to find \(f(g(0))\):
- First, substitute 0 into \(g(x)\) to find \(g(0) = 0^2 - 5 = -5\).
- Then, use \(-5\) as the input in \(f(x)\): \(f(-5) = -5 + 6 = 1\).
Quadratic Function
A quadratic function is one of the most common types of polynomial functions, characterized by the square of the input variable. It takes the general form \(g(x) = ax^2 + bx + c\). In our exercise, the quadratic function is \(g(x) = x^2 - 5\), which simplifies the general form to where \(a = 1\), \(b = 0\), and \(c = -5\).
Key properties of quadratic functions:
Key properties of quadratic functions:
- They graph as parabolas, which can open upwards or downwards depending on the sign of \(a\).
- The vertex of the parabola represents the maximum or minimum point.
- They have a symmetric axis that passes through the vertex.
Linear Function
Linear functions are the simplest type of polynomial functions. They form the equation \(f(x) = mx + b\), where \(m\) represents the slope and \(b\) the y-intercept. In this exercise, the linear function is given by \(f(x) = x + 6\). Here, the slope \(m\) is 1, and the y-intercept \(b\) is 6.
Characteristics of linear functions include:
Characteristics of linear functions include:
- Graphing as straight lines.
- Consistent slope, meaning no curves or sharp angles.
- Directly proportional relationship between \(x\) and \(f(x)\).