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Using (5.3) with (3.4) and (4.1), find Γ(3/2),Γ(-1/2), andΓ(-3/2)in terms ofπ.

Short Answer

Expert verified

The solution of the given gamma functions are as follows:

Γ32=π3Γ-12=-2πΓ-32=43π

Step by step solution

01

Given information

The given Gamma functions are Γ32,Γ-12 and Γ-32. Answers need to be expressed in terms of π.

02

Definition of a Gamma function

Gamma function is defined as Γ(p)=∫0∞xp-1e-xdx,p>0.

03

Write the relevant relations for Gamma functions

Write the relations of a Gamma function.

Γ12=πΓ(x)=1xΓ(x+1)Γ(x+1)=pΓ(x)

04

Substitute appropriate values and find the value of Gamma functions

Substitute32 with intoΓ(x)=1xΓ(x+1) and use the relations of gamma functions.

Γ32=12Γ12=π2

05

Repeat the process by making different substitutions.

Substitutex with-12 in the equation.

Γ(x)=1xΓ(x+1)Γ-12=1-12Γ12=-2π

Similarly,Substitute x with-32 in the equation.

Γ(x)=1xΓ(x+1)Γ-32=1-32Γ-12=43π

Thus, the required gamma functions are ,Γ12=π3,Γ-12=-2π and Γ-32=43π.

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