Q2P Solve聽(22.9) 聽to get(22.10) . ... [FREE SOLUTION]

Chapter 12: Q2P (page 611)

Solve $(22.9)$ to get $(22 .10)$ . If needed, see Chapter $(8)$ , Section 2. The given equation $(D + x) y_{0} = 0 toobtain y_{0} = e^{鈭� \frac{x^{2}}{2}} .$

Short Answer

Expert verified

Solving, $(D + x) y_{0} = 0$ results $y_{0} = e^{鈭� \frac{x^{2}}{2}}$ .

Step by step solution

Concept of Differential equation

Differential equations are equations that connect one or more derivatives of a function. This implies that their answer is a function.

Step 2:Solve the equations to obtain the solution

Determine equations for the solution as follows:

$\begin{matrix} (D + x) y_{0} = 0 \\ 鈬� \frac{d y_{0}}{d x} + x y_{0} = 0 \\ 鈬� \frac{d y_{0}}{d y_{0}} + x d x = 0 \\ 鈬� \log y_{0} + \frac{x^{2}}{2} = \log c \end{matrix}$

So, . $鈬� y_{0} = c e^{\frac{鈭� x^{2}}{2}}$

Let $y_{0} (0) = 1$ , then, $c = 1$ .

$y_{0} = e^{鈭� \frac{x^{2}}{2}}$

Therefore, solving $(D + x) y_{0} = 0$ , results $y_{0} = e^{鈭� \frac{x^{2}}{2}}$ .

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91影视

Solve $(22.9)$ to get $(22 .10)$ . If needed, see Chapter $(8)$ , Section 2. The given equation $(D + x) y_{0} = 0 toobtain y_{0} = e^{鈭� \frac{x^{2}}{2}} .$

Short Answer

Step by step solution

Concept of Differential equation

Step 2:Solve the equations to obtain the solution

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Most popular questions from this chapter

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91影视

Solve(22.9) to get(22.10) . If needed, see Chapter(8) , Section 2. The given equation(D+x)y0=0toobtainy0=e鈭�x22.

Short Answer

Step by step solution

Concept of Differential equation

Step 2:Solve the equations to obtain the solution

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Thermodynamics

Circular Motion and Gravitation

Magnetism and Electromagnetic Induction

Particle Model of Matter

Quantum Physics

Astrophysics

Study anywhere. Anytime. Across all devices.

Solve $(22.9)$ to get $(22 .10)$ . If needed, see Chapter $(8)$ , Section 2. The given equation $(D + x) y_{0} = 0 toobtain y_{0} = e^{鈭� \frac{x^{2}}{2}} .$