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Two decks of cards are 鈥渕atched,鈥 that is, the order of the cards in the decks is compared by turning the cards over one by one from the two decks simultaneously; a 鈥渕atch鈥 means that the two cards are identical. Show that the probability of at least one match is nearly.11/e

Short Answer

Expert verified

The probability of at least one match is nearly11/ehas been proved.

Step by step solution

01

Given Information 

It has been given that two decks of cards are 鈥渕atched,鈥 that is, the order of the cards in the decks is compared by turning the cards over one by one from the two decks simultaneously; a 鈥渕atch鈥 means that the two cards are identical

02

Definition of Probability 

Probability means the chances of any event to occur is called it probability.

03

Find the probability 

The Poisson distribution is given by the expression mentioned below.

P(x)=xex!

Assume that there is no cards match so the average.

=np=n(1n)=1

All couples are equally likely, the probability of getting no match is given by expression mentioned below.

p(0)=10e10!=e1

Now the probability of getting at least one couples is given by expression mentioned below.

p(x>0)=1p(0)=1e1=11e

Hence, it has been proved.

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Most popular questions from this chapter

Two cards are drawn at random from a shuffled deck.

  1. What is the probability that at least one is a heart?

(b) If you know that at least one is a heart, what is the probability that both are

hearts?

(a) Following the methods of Examples 3,4,5, show that the number of equally likely ways of putting N particles in n boxes,n>N, nNisfor Maxwell Boltzmann particles, C(n,N)for Fermi-Dirac particles, C(n1+N,N)andfor Bose-Einstein particles.

(b) Show that if n is much larger than N (think, for example, ofn=106,N=10), then both the Bose-Einstein and the Fermi-Dirac results in part (a) contain products of N numbers, each number approximately equal to n. Thus show that for n N, both the BE and the FD results are approximately equal tonNN!which is1N!times the MB result.

(a) Note that (3.4) assumes P(A) is not equal to 0 since PA(B)is meaningless if P(A) = 0.

Assuming both P(A) is not equal to 0 and P(B) is not equal to 0, show that if (3.4) is true, then

P(A)=PA(B)that is if B is independent of A, then A is independent of B.

If either P(A) or P(B) is zero, then we use (3.5) to define independence.

(b) When is an event E independent of itself? When is E independent of鈥渘ot E鈥?

Use Problem 9to find xin Problem7.

:(a) Suppose that Martian dice are regular tetrahedra with vertices labelled 1 to 4. Two such dice are tossed and the sum of the numbers showing is even. Let x be this sum. Set up the sample space for x and the associated probabilities.

(b) Find E(x) and.

(c) Find the probability of exactly fifteen 2鈥檚 in 48 tosses of a Martian die using the binomial distribution.

(d) Approximate (c) using the normal distribution.

(e) Approximate (c) using the Poisson distribution.

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