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Find ddx∫t=1xt=2xcoshxttdt.

Short Answer

Expert verified

The value ofddx∫t=1xt=2xcoshxttdtis0 .

Step by step solution

01

Given Information

Given that ddx∫t=1xt=2xcoshxttdt. ...(1)

02

Formula Used

We know that ddx∫u(x)v(x)f(x,t)dt=f(x,v)dvdx-f(x,u)dudx+∫uv∂f∂xdt ...(2)

03

Solving the given equation

Compare equation (1) and equation (2).

ddx∫t=1xt=2xcoshxttdt=coshx2x2x×ddx2x-coshx1x1x×ddx1x+∫t=1xt=2xsinhxttdtddx∫t=1xt=2xcoshxttdt=cosh2×x2-2x2-cosh1×x×-1x2+coshxtx1x2xddx∫t=1xt=2xcoshxttdt=-1xcosh2-cosh1-1x+1xcoshx2x-coshx1x

Solving Further,

ddx∫t=1xt=2xcoshxttdt=-1xcosh2--1xcosh1+1xcosh2-1xcosh1ddx∫t=1xt=2xcoshxttdt=-1xcosh2+1xcosh1+1xcosh2-1xcosh1ddx∫t=1xt=2xcoshxttdt=0

Hence the value of ddx∫t=1xt=2xcoshxttdt=0.

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