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Test the following series for convergence

∑n-1∞(-1)nnn+5

Short Answer

Expert verified

The alternating series∑n-1∞(-1)nnn+5 diverges.

Step by step solution

01

Significance of alternating series

If the terms' absolute values gradually decline to zero, or if|an+1|≤|an|andlimn→∞an=0, then an alternating series converges.

02

Use a test to check for convergence

Consider the alternating series,

∑n-1∞(-1)nnn+5

Use the below test to check the series for convergence:

|an+1|≤|an|andlimn→∞an=0.

The series converges if the condition is met.

an=n(-1)nn+5an=nn+5an+1=n+1n+6

03

Perform the test to check if both conditions are met

Let check ifan>an+1 and using the following method.

Foran+1-an<0 this will mean thatan>an+1

Foran+1-an>0 this will mean thatan<an+1

an+1-an=n+1n+6-nn+5=n2+6n+5-n2-6n(n+5)(n+6)=5(n+5)(n+6)

Now, forn≥1,an+1-an>0,an<an+1

Therefore, we conclude thatan+1>an forn≥1

As the first condition is not met, so the series diverges.

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