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91Ó°ÊÓ

Show that if p is a positive integer, thenpn=0when n>p , so (1+x)p=∑pnxnis just a sum ofp+1terms, from n=0 to n=p . For example,(1+x)2has 3 terms,(1+x)3 has4terms, etc. This is just the familiar binomial theorem.

Short Answer

Expert verified

The statement has been proven.

Step by step solution

01

Given Information

Thebinomial series.

02

Definition of the binomial series.

The Taylor series for the function given by is the binomial series, where is an arbitrary complex number.

03

Prove the statement.

The binomial series states that (1+x)p=∑n=0∞pnxn

The formula states thatpn=p(p-1)(p-2)…(p-n+1)n!

localid="1657347784194" pn=p(p-1)(p-2)…(p-p)…(p-n+1)n!

localid="1657347855207" p(p-1)(p-2)…(p-p)…(p-n+1)n!=0

localid="1657347906098" p!p!(p-p)!=1

localid="1657347974064" pn≠0 only for localid="1657348003107" n≤pandlocalid="1657348034900" n≥0

Solve further.

localid="1657348111696" (1+x)p=∑n=0∞pnxn

localid="1657348136816" (1+x)p=p0+p1x+p2x2+p3x3+…+ppxp

The expansion haslocalid="1657348245474" p+1terms for localid="1657348169040" n=0-p
.

The statement has been proven.

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