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Use the integral test to show that∑n=0∞e-n2 converges.

Short Answer

Expert verified

The series∑n=0∞e-n2 is convergent.

Step by step solution

01

Definition of Gaussian integral, convergent, and divergent

  • The Gaussian integral which is also known as Poisson integral. The area of Gaussian function f(x)=e-x2and over the x-axis is as follows:

∫-∞∞e-x2dx=π

Then, half of the area of Gaussian function and -axis is: ∫0∞e-x2dx=π2.

  • If the partial sum localid="1664193252645" Snof an infinite series tend to a limit Sthen the series is called convergent. If the partial sums Sn of an infinite series do not approach a limit, the series is called divergent. The limiting value S is called the sum of the series.
02

Apply the integral test

Given that the limit is∑n=0∞e-n2.

Now, apply the integral test as:

∫0∞e-n2dn

This is half of the area of Gaussian function and x-axis which is, ∫0∞e-n2dn=π2.

The integral value is finite, therefore the given series∑n=0∞e-n2converges.

03

Solve the integral

Now, compare with the integral∫∞e-ndn.

Evaluate the integral is as follows:

∫∞e-ndn=e-n-1∞=-e-∞=0

The integral value is finite, therefore the integral∫∞e-ndn converges. Here, both the integral converges.

Hence, it is proved that series∑n=0∞e-n2 converges.

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