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x2ln(1-x)

Short Answer

Expert verified

The series isx2ln(1-x)=-∑n=1∞xn+2n

The sum is given below.

S1=-x3

S2=-x3--x42

S3=-x3--x42--x53

The graphs are shown below.

Step by step solution

01

Given Information

The Maclaurin series.

02

Definition of the Maclaurin Series.

A Maclaurin series is a function with an expansion series that gives the sum of the function's derivatives.

03

Find the series and sum.

The Maclaurin series is given below.

ln(1+x)=x-x22+x33-x44+…

ln(1-x)=-x-x22-x33-x44+…

x2ln(1-x)=-x3-x42-x53-…

The general series is given below x2ln(1-x)=-x3-x42-x53-…-xn+2n

x2ln(1-x)=-∑n=1∞xn+2n

The sum is given below.

S1=-x3

S2=-x3--x42

S3=-x3--x42--x53

04

Plot the graphs.

The graph of the function with S1,S2,S3is given below.

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