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Repeat Problem 14b for the following points and directions.

(a)(4,2),i^+j^(b)(-3,1),4i^+3j^(c)(2,2),-3i^+j^(d)(-4,-1),4i^-3j^

Short Answer

Expert verified

(a)42upwards(b)0samelevel(c)-410downwards(d)85upwards

Step by step solution

01

Given Information.

The given equation is∇ϕ=-2xi^-8yj^-k^

02

Definition of a gradient.

Gradient is definedby the equation mentioned below.

∇ϕ=∂ϕ∂xi^+∂ϕ∂yj^+∂ϕ∂zk^

03

Find the rate of movement of the function at the given value of u.

At u→=(1,1,0), calculate the function.

Ï•=32-x2-4y2-z=0

Find the directional derivate of the function.

dϕdu^=(∇ϕ)·u^u^=12(1,1,0)

Calculate the gradient of the function.

∇ϕ=-8i^+16j^-k^

Substitute the values to find the directional derivate.

dϕdu^=12(1,1,0)·(-8,16,-1)=42

From the sign, deduce that the movement is in the upward direction.

04

Repeat the process for the second point.

The second point is u→=(-3,1,0)u→=(-3,1,0).

Calculate the unit vector

u^=15(4,3,0)

Calculate the gradient of the function.

∇ϕ=6i^-8j^-k^

Substitute the values to find the directional derivate.

dϕdu^=15(4,3,0)·(6,-8,-1)=0

From the sign, deduce that the movement is neither upwards nor downwards but in the same direction.

05

Repeat the process for the third point.

The third point is .u→=(2,2,0)

Calculate the unit vector

u^=110(-3,1,0)

Calculate the gradient of the function

∇ϕ=-4i^-16j^-k^

Substitute the values to find the directional derivate.

dϕdu^=110(-3,1,0)·(-4,-16,-1)=-410

From the sign, deduce that the movement is in the downward direction.

06

Repeat the process for the fourth point.

The third point is .u→=(-4,-1,0)

Calculate the unit vector

u^=15(4,-3,0)

Calculate the gradient of the function

∇ϕ=-8i^+24j^-k^

Substitute the values to find the directional derivate

dϕdu^=15(4,-3,0)·(8,8,-1)=85

From the sign, deduce that the movement is in the upward direction.

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