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Find the Maclaurin series for the following functions cos[ln(1 + x)]:

Short Answer

Expert verified

Maclaurin series of cos[ln(1+x)]is x22+x32-5x412+…….

Step by step solution

01

Concept and formula used to find the Maclaurin series of the given function 

The Maclaurin series ofcosxis expressed as follows:

cosx=1-x22+x424+…….

The Maclaurin series of ln(1+x)is expressed as follows:

ln(1+x)=x-x22+x33-x44……..

ln(1+x)=x-x22+x33-x44……..

02

Calculation to find the Maclaurin series of the function cos [1n(1 + x)]:

Substitutex-x22+x33-x44……. forx in expansion of cosxas follows:

role="math" localid="1664264756169" cos[ln(1+x)]=1-x-x22+x33-x44……22+x-x22+x33-x44……424+……cos[ln(1+x)]=1--576x2+576x3-480x41152+…….cos[ln(1+x)]=x22+x32-5x412+…….

Thus, the Maclaurin series of role="math" localid="1664264808184" cos[ln(1+x)] is x22+x32-5x412+…….

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