91Ó°ÊÓ

The given expression is $e^{iarc\sin i}$.

The numbers that are presented in the form of $\mathit{x}\mathbf{+}\mathit{i}\mathit{y}$where, $\mathbf{\text{'}}\mathit{x}\mathbf{\text{'}}$is real numbers and $\mathbf{\text{'}}\mathit{i}\mathit{y}\mathbf{\text{'}}$ is an imaginary number, those numbers are referred to as called Complex numbers.

Consider $w=e^{iarc\sin i}$

Let $\arcsin \mathit{\left(}i\mathit{\right)}$be $z$.

$z=\arcsin \left(i\right)$

$\sin \left(z\right)=i$ …(1)

$w=e^{\left(iz\right)}$ …(2)

The exponential form of $\sin \left(z\right)=\frac{e^{\left(zi\right)}-e^{\left(-zi\right)}}{2i}$ …(3)

Put equation (3) in (1).

$\frac{e^{\left(zi\right)}-e^{\left(-zi\right)}}{2i}=i$ …(4)

Simplify equation (4).

$$\begin{gathered} e^{\left(zi\right)}-e^{\left(-zi\right)}=-2 \\ {e}^{\left(2zi\right)}+2e^{\left(zi\right)}-1=0 \end{gathered}$$

.....(5)

Let $e^{iz}$be$u$.

$u^2+2u-1=0$

Solve by using quadratic formula $u=\frac{-b\underline{+}\sqrt{b^2-4ac}}{2a}$.

Coefficients of the quadratic equation are as follows.

$$\begin{gathered} a=1 \\ b=2 \\ c=-1 \end{gathered}$$

Substitute the coefficients into the quadratic formula.

$$\begin{gathered} u=\frac{-2\underline{+}\sqrt{4-4\left(-1\right)}}{2} \\ =-1\underline{+}\sqrt{2} \end{gathered}$$

The two solutions $u_1$, $u_2$are $\left(-1+\sqrt{2}\right),\left(-1-\sqrt{2}\right)$respectively.

Find the value of $i{z}_1$.

$$\begin{gathered} i{z}_1=\mathrm{In}\left(u_{\mathit{1}}\right) \\ =\mathrm{In}\left[e^{\left(z_{1}i\right)}\right] \\ =\mathrm{In}\left(\sqrt{2}-1\right) \\ {\mathrm{iz}}_1=\mathrm{In}\left(\sqrt{2}-1\right)\underline{+}2n\mathrm{Ï€}i \end{gathered}$$ ....(6) Find the value of $i{z}_2$.

$$\begin{gathered} i{z}_2=\mathrm{In}\left(u_2\right) \\ =\mathrm{In}\left[e^{\left(z_{2}i\right)}\right] \\ =\mathrm{In}\left(-\sqrt{2}-1\right) \\ i{z}_2=\mathrm{In}\left(\sqrt{2}+1\right)+i\left(\mathrm{Ï€}\underline{+}2\mathrm{²ÔÏ€}\right) \end{gathered}$$ ......(7)

Find the value of$w_1$.

$w_1=e^{i{z}_1}$ …(8)

Put equation (6) in (8).

$$\begin{gathered} w_1=e^{\left[\mathrm{In}\left(\sqrt{2}-1\right)\underline{+}2n\mathrm{Ï€}i\right]} \\ =e^{\mathrm{In}\left(\sqrt{2}-1\right)}.e^{2n\mathrm{Ï€¾\pm }} \\ =\sqrt{2}-1 \\ =0.414 \end{gathered}$$

Find the value$w_2$

$w_2=e^{i{z}_2}$ …(9)

Put equation (7) in (9).

$$\begin{gathered} w_2=e^{\left[In\left(\sqrt{2}+1\right)+\left(\mathrm{Ï€}\underline{+}2\mathrm{²ÔÏ€}\right)i\right]} \\ =e^{In\left(\sqrt{2}-1\right)}.e^{\left(\mathrm{Ï€}\underline{+}2\mathrm{²ÔÏ€}\right)i} \\ =\left[\sqrt{2}-1\right].\left[\cos \left(\mathrm{Ï€}\underline{+}2\mathrm{²ÔÏ€}\right)+i\sin \left(\mathrm{Ï€}\underline{+}2\mathrm{²ÔÏ€}\right)\right] \\ =-2.414 \end{gathered}$$

Hence the values of $e^{iarc\sin i}$are $0.414,-2.414$.