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Without consulting Figure \(2.8\) or Table \(2.2\), determine whether each of the following electron configurations is an inert gas, a halogen, an alkali metal, an alkaline earth metal, or a transition metal. Justify your choices. (a) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}\) (b) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{7} 4 s^{2}\) (c) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6}\) (d) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}\) (e) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 4 d^{5} 5 s^{2}\) (f) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}\)

Short Answer

Expert verified
Question: Identify the element type (inert gas, halogen, alkali metal, alkaline earth metal, or transition metal) based on the following electron configurations: (a) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}\) (b) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{7} 4 s^{2}\) (c) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6}\) (d) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}\) (e) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 4 d^{5} 5 s^{2}\) (f) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}\) Answer: (a) Halogen (b) Transition metal (c) Inert gas (d) Alkali metal (e) Transition metal (f) Alkaline earth metal

Step by step solution

01

Determine the valence shell configuration

The outer shell is in the 3rd energy level: \(3s^2 3p^5\). It is one electron less than a fully filled shell, so it's a halogen. (b) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{7} 4 s^{2}\)
02

Determine the valence shell configuration

The outer shell configuration is \(3d^7 4s^2\), which has partially filled \(d\) orbitals, so it's a transition metal. (c) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6}\)
03

Determine the valence shell configuration

The outer shell is in the 4th energy level: \(4s^2 4p^6\). It is a fully filled shell, so it's an inert gas. (d) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{1}\)
04

Determine the valence shell configuration

The outer shell is in the 4th energy level: \(4s^1\). It has one electron in it, so it's an alkali metal. (e) $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2} 4 p^{6} 4 d^{5} 5 s^{2}$
05

Determine the valence shell configuration

The outer shell configuration is \(4d^5 5s^2\), which has partially filled \(d\) orbitals, so it's a transition metal. (f) \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2}\)
06

Determine the valence shell configuration

The outer shell is in the 3rd energy level: \(3s^2\). It has two electrons in it, so it's an alkaline earth metal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inert Gas
An inert gas, also known as a noble gas, possesses a fully filled valence electron shell, which makes these elements particularly stable and unreactive chemically. For instance, the electron configuration of an inert gas ends with a completed 'p' orbital, such as in helium (\texttt{He}: \(1s^2\)), neon (\texttt{Ne}: \(1s^2 2s^2 2p^6\)), or argon (\texttt{Ar}: \(1s^2 2s^2 2p^6 3s^2 3p^6\)).

In our exercise, Example (c) \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6\) fits this criterion and thus represents an inert gas, which in this case is krypton (\texttt{Kr}). It is essential to identify this electron configuration to understand the non-reactivity of these elements, which is a fundamental concept in chemistry.
Halogen
Halogens have electron configurations that end with their 'p' orbitals being one electron short of being full. This missing electron gives them a high reactivity as they seek to fill their valence shell through chemical bonding. Common halogens include fluorine (\texttt{F}), chlorine (\texttt{Cl}), and bromine (\texttt{Br}).

In Example (a) with the configuration \(1s^2 2s^2 2p^6 3s^2 3p^5\), we see that the valence shell has a configuration of \(3s^2 3p^5\), which is one electron away from the stable inert gas configuration, fitting a halogen's description. Understanding the reactive nature of halogens is critical for mastering concepts in chemical reactions and bonding.
Alkali Metal
Alkali metals are characterized by having a single electron in their outermost 's' orbital (\(ns^1\)), making them highly reactive and eager to lose that single electron to reach the noble gas configuration. Alkali metals include lithium (\texttt{Li}), sodium (\texttt{Na}), and potassium (\texttt{K}).

Look at Example (d)'s configuration \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^1\), where the outer shell of the atom has a single electron, \(4s^1\), indicating an alkali metal, specifically potassium (\texttt{K}). Knowing this configuration helps students make connections to the properties of alkali metals, such as their ability to conduct electricity and their vigorous reactions with water.
Alkaline Earth Metal
Alkaline earth metals have two electrons in their outermost 's' orbital (\(ns^2\)), making them less reactive than alkali metals but still quite reactive. These metals, which include beryllium (\texttt{Be}), magnesium (\texttt{Mg}), and calcium (\texttt{Ca}), tend to lose two electrons to form stable ions with a +2 charge.

In Example (f), we observe the configuration \(1s^2 2s^2 2p^6 3s^2\), which represents the outer shell configuration of an alkaline earth metal. Recognizing these configurations is helpful, especially when predicting the behavior of such elements in compounds and during chemical reactions.
Transition Metal
Transition metals distinguish themselves with partially filled 'd' orbitals. Their electron configurations can vary, but one key characteristic is that after the '4s' orbital is filled, electrons begin to populate the '3d' orbitals. Transition metals, such as iron (\texttt{Fe}), copper (\texttt{Cu}), and zinc (\texttt{Zn}), often form colorful compounds and can exhibit multiple oxidation states.

In our exercise, both Example (b) \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^7 4s^2\) and Example (e) \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^5 5s^2\) feature such configurations, indicating transition metals. Understanding electron configurations in transition metals aids in explaining their variable chemical behavior, catalytic activity, and the formation of alloys, all of which are important in industrial and technological applications.

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Most popular questions from this chapter

For the \(K\) shell, the four quantum numbers for each of the two electrons in the \(1 s\) state, in the order of \(n l m_{l} m_{s}\), are \(100 \frac{1}{2}\) and \(100\left(-\frac{1}{2}\right)\). Write the four quantum numbers for all of the electrons in the \(L\) and \(M\) shells, and note which correspond to the \(s, p\), and \(d\) subshells.

(a) Cite two important quantum-mechanical concepts associated with the Bohr model of the atom. (b) Cite two important additional refinements that resulted from the wave- mechanical atomic model.

The net potential energy \(E_{N}\) between two adjacent ions is sometimes represented by the expression $$ E_{N}=-\frac{C}{r}+D \exp \left(-\frac{r}{\rho}\right) $$ in which \(r\) is the interionic separation and \(C, D\), and \(\rho\) are constants whose values depend on the specific material. (a) Derive an expression for the bonding energy \(E_{0}\) in terms of the equilibrium interionic separation \(r_{0}\) and the constants \(D\) and \(\rho\) using the following procedure: (i) Differentiate \(E_{N}\) with respect to \(r\), and set the resulting expression equal to zero. (ii) Solve for \(C\) in terms of \(D, \rho\), and \(r_{0}\). (iii) Determine the expression for \(E_{0}\) by substitution for \(C\) in Equation \(2.18\). (b) Derive another expression for \(E_{0}\) in terms of \(r_{0}, C\), and \(\rho\) using a procedure analogous to the one outlined in part (a).

Relative to electrons and electron states, what does each of the four quantum numbers specify?

Explain why hydrogen fluoride (HF) has a higher boiling temperature than hydrogen chloride \((\mathrm{HCl})\left(19.4^{\circ} \mathrm{C}\right.\) vs. \(\left.-85^{\circ} \mathrm{C}\right)\), even though HF has a lower molecular weight.

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