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Chapter 2: Problem 12

To what group in the periodic table would an element with atomic number 112 belong?

Short Answer

Expert verified
Answer: The element with atomic number 112 belongs to Group 14 (IVA) in the periodic table.

Step by step solution

01

Determine the electron configuration of the element

First, we need to determine the electron configuration of the element with atomic number 112. The element has 112 electrons, and we need to distribute these electrons into various energy levels and subshells according to the Aufbau principle.
02

Find out the outermost electrons

The electron configuration of the element with atomic number 112 can be written as: 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^10 6p^6 7s^2 5f^14 6d^10 7p^2. We can observe that the outermost electrons are in the 7s and 7p orbitals. There are 2 electrons in the 7s orbital and 2 electrons in the 7p orbital.
03

Identify the group of the element

To find the group of the element, we need to count the number of valence electrons. In this case, the valence electrons are in the 7s and 7p orbitals, and there are a total of 4 valence electrons. Therefore, the element with atomic number 112 belongs to Group 14 (IVA) in the periodic table.

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Most popular questions from this chapter

The net potential energy \(E_{N}\) between two adjacent ions is sometimes represented by the expression $$ E_{N}=-\frac{C}{r}+D \exp \left(-\frac{r}{\rho}\right) $$ in which \(r\) is the interionic separation and \(C, D\), and \(\rho\) are constants whose values depend on the specific material. (a) Derive an expression for the bonding energy \(E_{0}\) in terms of the equilibrium interionic separation \(r_{0}\) and the constants \(D\) and \(\rho\) using the following procedure: (i) Differentiate \(E_{N}\) with respect to \(r\), and set the resulting expression equal to zero. (ii) Solve for \(C\) in terms of \(D, \rho\), and \(r_{0}\). (iii) Determine the expression for \(E_{0}\) by substitution for \(C\) in Equation \(2.18\). (b) Derive another expression for \(E_{0}\) in terms of \(r_{0}, C\), and \(\rho\) using a procedure analogous to the one outlined in part (a).

(a) Calculate \%IC of the interatomic bonds for the intermetallic compound \(\mathrm{Al}_{6} \mathrm{Mn}\). (b) On the basis of this result, what type of interatomic bonding would you expect to be found in \(\mathrm{Al}_{6} \mathrm{Mn}\) ?

What type(s) of bonding would be expected for each of the following materials: solid xenon, calcium fluoride \(\left(\mathrm{CaF}_{2}\right)\), bronze, cadmium telluride (CdTe), rubber, and tungsten?

(a) Briefly cite the main differences among ionic, covalent, and metallic bonding. (b) State the Pauli exclusion principle.

Zinc has five naturally occurring isotopes: \(48.63 \%\) of \({ }^{64} \mathrm{Zn}\), with an atomic weight of \(63.929 \mathrm{amu}\); \(27.90 \%\) of \(^{66} \mathrm{Zn}\), with an atomic weight of \(65.926\) amu; \(4.10 \%\) of \({ }^{67} \mathrm{Zn}\), with an atomic weight of \(66.927 \mathrm{amu} ; 18.75 \%\) of \({ }^{68} \mathrm{Zn}\), with an atomic weight of \(67.925\) amu; and \(0.62 \%\) of \({ }^{70} \mathrm{Zn}\), with an atomic weight of \(69.925\) amu. Calculate the average atomic weight of \(Z n\).
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