Chapter 5: Problem 1
Briefly explain the difference between self diffusion and inter diffusion.
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Chapter 5: Problem 1
Briefly explain the difference between self diffusion and inter diffusion.
These are the key concepts you need to understand to accurately answer the question.
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Briefly explain the concept of steady state as it applies to diffusion.
The preexponential and activation energy for the diffusion of chromium in nickel are \(1.1 \times 10^{-4} \mathrm{m}^{2} / \mathrm{s}\) and \(272,000 \mathrm{J} / \mathrm{mol},\) respec- tively. At what temperature will the diffusion coefficient have a value of \(1.2 \times 10^{-14} \mathrm{m}^{2} / \mathrm{s} ?\)
An FCC iron-carbon alloy initially containing 0.10 wt \(\% \mathrm{C}\) is carburized at an elevated temperature and in an atmosphere wherein the surface carbon concentration is maintained at 1.10 wt\%. If after 48 h the concentration of carbon is \(0.30 \mathrm{wt} \%\) at a position \(3.5 \mathrm{mm}\) below the surface, determine the temperature at which the treatment was carried out.
The steady-state diffusion flux through a metal plate is \(7.8 \times 10^{-8} \mathrm{kg} / \mathrm{m}^{2}-\mathrm{s}\) at a tem- perature of \(1200^{\circ} \mathrm{C}(1473 \mathrm{K})\) and when the concentration gradient is \(-500 \mathrm{kg} / \mathrm{m}^{4}\). Calculate the diffusion flux at \(1000^{\circ} \mathrm{C}(1273 \mathrm{K})\) for the same concentration gradient and assuming an activation energy for diffusion of \(145,000 \mathrm{J} / \mathrm{mol}\).
Nitrogen from a gaseous phase is to be diffused into pure iron at \(675^{\circ} \mathrm{C}\). If the surface concentration is maintained at \(0.2 \mathrm{wt} \% \mathrm{N}\) what will be the concentration \(2 \mathrm{mm}\) from the surface after 25 h? The diffusion coefficient for nitrogen in iron at \(675^{\circ} \mathrm{C}\) is \(1.9 \times 10^{-11} \mathrm{m}^{2} / \mathrm{s}\).
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