/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 A bullet of mass \(M\) hits a bl... [FREE SOLUTION] | 91Ó°ÊÓ

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A bullet of mass \(M\) hits a block of mass \(M^{\prime}\). The energy transfer is maximum, when (a) \(M^{*}=M\) (b) \(M^{\prime}=2 M\) (c) \(M^{\prime}<M\)

Short Answer

Expert verified
The energy transfer is maximum when \( M' = M \) (option a).

Step by step solution

01

Understand the Energy Transfer

To maximize energy transfer, we need to consider the system's kinetic energy during and after the collision. Maximum energy transfer occurs when both objects move together after the collision.
02

Analyze the System's Momentum

The initial momentum is carried by the bullet and after the collision, both the bullet and the block share this momentum. Use conservation of momentum: \[ Mv = (M + M') v' \] where \( v \) is the initial velocity of the bullet and \( v' \) is the velocity after collision.
03

Determine Final Velocity

Solve for the final velocity \( v' \): \[ v' = \frac{Mv}{M + M'} \]This shows the relationship between the masses and the final velocity.
04

Calculate Kinetic Energy Initially and Finally

Initial kinetic energy is \( E_{initial} = \frac{1}{2} M v^2 \).Final kinetic energy when both objects move together is: \[ E_{final} = \frac{1}{2} (M + M') \left( \frac{Mv}{M + M'} \right)^2 \]
05

Maximize Energy Transfer Calculation

Energy transferred is given by the difference between initial and final kinetic energy: \[ \Delta E = E_{initial} - E_{final} \] To maximize \( \Delta E \), solve \[ E_{final} = \frac{M^2 v^2}{2(M + M')} \] setting \( \frac{d}{dM'} \left[ \frac{M^2}{M + M'} \right] = 0 \) to reveal the condition for maximum transfer.
06

Solve for Condition

Solving the derivative for maximum energy transfer gives the result: \[ M' = M \] Thus, option \( (a) \) is correct since energy transfer is maximum when \( M' = M \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Conservation
When studying collisions, momentum conservation is a fundamental principle. It states that the total momentum of a closed system remains constant before and after an event, like a collision. In simple terms, the initial momentum carried by a moving object (in this case, a bullet with mass \(M\) and velocity \(v\)) is redistributed amongst all objects involved in the collision after it occurs.
In the provided exercise, the bullet collides with a block of mass \(M'\), and they move together post-collision. The equation representing momentum conservation is:
  • Initial momentum: \( Mv \)
  • Final momentum: \((M + M')v'\)
This can be set up as \( Mv = (M + M')v' \). Here, \(v'\) is the velocity of the combined mass after collision. Solving for \(v'\) helps us understand how momentum is divided across the two masses, which is critical for further calculations regarding kinetic energy.
Kinetic Energy Calculation
Kinetic energy measures the energy that an object possesses due to its motion. When a bullet with mass \(M\) and initial velocity \(v\) collides with a block, the focus is often on how kinetic energy changes throughout the collision.
The initial kinetic energy \( E_{initial} \) is given by the formula:
  • \( E_{initial} = \frac{1}{2} M v^2 \)
After the collision, where the bullet and the block stick together, the final kinetic energy \( E_{final} \) is given by:
  • \( E_{final} = \frac{1}{2} (M + M') \left( \frac{Mv}{M + M'} \right)^2 \)
These calculations are crucial because they lay the foundation for understanding how much kinetic energy has been transferred or lost in the process. Comparing \( E_{initial} \) and \( E_{final} \) helps us determine the energy transfer in the collision.
Maximum Energy Transfer Conditions
The goal in analyzing this type of collision problem often revolves around determining the condition for maximum energy transfer. To find this, we look at the change in kinetic energy, expressed as \( \Delta E = E_{initial} - E_{final} \). This difference indicates how much energy has been transferred from the bullet to the block.
Through detailed analysis and calculations, it has been found that maximum energy transfer occurs when the masses of the bullet and block are equal, i.e., \( M' = M \). This conclusion is derived by setting the derivative of the function describing energy distribution post-collision to zero, revealing that setting the masses equal maximizes \( \Delta E \).
This scenario allows energy to be shared optimally between the two bodies, thereby achieving the condition for maximum energy transfer during the collision.

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Most popular questions from this chapter

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