/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 When a meteorite burns in the at... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

When a meteorite burns in the atmosphere, then (a) the momentum conservation principle is applicable to the meteorite system (b) the energy of meteorite remains constant (c) the conservation principle of momentum is applicable to a system consisting of meteorites, earth and air molecules (d) the momentum of metearite remains constant

Short Answer

Expert verified
(c) The conservation principle of momentum applies to the system of meteorite, Earth, and air molecules.

Step by step solution

01

Understand the Scenario

When a meteorite enters Earth's atmosphere, it experiences a significant amount of resistance and starts burning due to the friction with air molecules. This interaction influences both momentum and energy conservation.
02

Analyze Momentum Conservation for the Meteorite Alone

The momentum conservation principle states that the total momentum of an isolated system remains constant. However, in this case, the meteorite is not isolated due to the external forces exerted by air resistance and gravity. Thus, the momentum of the meteorite alone is not conserved.
03

Examine Energy Changes in the Meteorite

As the meteorite burns, it loses energy in the form of heat, light, and thermal energy due to friction. Therefore, the total energy of the meteorite does not remain constant as it transforms and dissipates.
04

Consider the Larger System: Meteorite, Earth, and Air

If we consider a larger system that includes the meteorite, Earth, and the surrounding air molecules, the principle of conservation of momentum does apply. This is because any force exerted by the meteorite is counteracted by the system, making it an isolated system concerning momentum.
05

Verify if Meteorite Momentum Remains Constant

Given that the meteorite is subject to external forces (air resistance and gravity), its momentum changes as it descends through the atmosphere. Hence, the momentum of the meteorite alone does not remain constant.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum Conservation Principle
The principle of momentum conservation is a fundamental concept in physics. It tells us that the total momentum within an isolated system remains unchanged. In simpler terms, if no external forces are acting on a system, the sum of the momentum will stay the same. This principle is important when studying systems of colliding objects.

However, real-life situations often involve external forces, such as air resistance, which impact momentum conservation. For a meteorite plunging into Earth's atmosphere, external forces like air resistance and gravity are substantial. These forces make the meteorite system "non-isolated." This means the meteorite's momentum itself will change as it loses speed and burns up in the atmosphere.

To find a condition where momentum conservation holds, consider expanding the system to include not just the meteorite but also Earth and its atmosphere. In this larger system, the momentum changes experienced by the meteorite are balanced by the momentum changes in air molecules, keeping the overall momentum constant.
Energy Conservation in Meteorites
Energy conservation deals with how the total energy of an isolated system remains constant. Energy can change forms, like potential energy converting to kinetic energy, but the sum remains the same.

For meteorites, their journey through the atmosphere changes their energy drastically. As friction transforms kinetic energy into heat and light, the once conserved energy seems to disappear. It may seem that the meteorite's energy is not conserved, but it is merely transforming. The energy is not lost; instead, it is dissipated into the environment as heat and light.

Remember:
  • Energy isn't lost; it changes forms.
  • Dissipated energy contributes to the heat of the air.
In a comprehensive view considering the meteorite, Earth, and the surrounding air, energy conservation principles still apply as all forms of energy are accounted for.
Effects of Air Resistance on Meteors
Air resistance plays a crucial role when a meteorite enters Earth's atmosphere. It's an external force that deeply affects the motion of the meteorite. As the meteorite travels at high speeds, it encounters air molecules, and this interaction causes frictional force.

Friction converts the meteorite's kinetic energy into other energy forms like heat and light. It dramatically slows down the meteorite by reducing its kinetic energy, which results in loss of speed. This can eventually cause the meteorite to disintegrate or entirely burn up before reaching the ground.

Important Points About Air Resistance:
  • Causes the meteor to heat up due to friction.
  • Reduces speed, impacting both momentum and energy.
  • Can lead to complete vaporization of the meteor.
Thus, air resistance changes both momentum and energy perspectives for meteorites traveling through the atmosphere.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assertion-Retson type. Each of these contains two Statements: Statement I (Assertion), Statement \(\Pi\) (Rotson). Fach of these questions also has fomr alternatitue choice, only ane of uhich is correct. You hatee to select the correct choices from the coves (al, (b), (c) and (d) ginvn bolow (a) If both Assertion and Reason are true and the Reason is correct explanation of the Assertion (b) If both Assertion and Reason are true but Reason is not correct explanation of the Assertion (c) If Assertion is true but Reason is false (d) If Assertion is false but the Reason is true Assertion A quick collision between two bodies is more violent than slow collision even when initial and final velocities are identical. Reason The rate of change of momentum determines that force is small or large.

A tennis ball is dropped from a height \(h_{0}\) on a horizontal marble flooring. The ball rebounds to a height \(h_{1}\), then again falls on the floor, again rebounds and so on. If \(h_{0}=10 \mathrm{~m}\) and \(e=1 / 2\), then compute the total distance travelled by the ball before it stops bouneing. |al \(\infty\) (b) \(50 \mathrm{~m}\) (c) \(\frac{50}{3} \mathrm{~m}\) (d) \(\frac{25}{3} \mathrm{~m}\)

A bullet of mass \(M\) hits a block of mass \(M^{\prime}\). The energy transfer is maximum, when (a) \(M^{*}=M\) (b) \(M^{\prime}=2 M\) (c) \(M^{\prime}<M\)

A bullet of mass \(20 \mathrm{~g}\) and moving with \(600 \mathrm{~ms}^{-1}\) collides with a block of mass \(4 \mathrm{~kg}\) hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height \(0.2 \mathrm{~m}\) after collision? IUP SEE 2006] (a) \(200 \mathrm{~ms}^{-1}\) (b) \(150 \mathrm{~ms}^{-1}\) (c) \(400 \mathrm{~ms}^{-1}\) (d) \(300 \mathrm{~ms}^{-1}\)

A mass \(m\) moves with a velocity \(v\) and collides inelastically with another identical mass. After collision the lst mass moves with velocity \(\frac{v}{\sqrt{3}}\) in a direction perpendicular to the initial direction of motion. Find the speed of the 2nd mass after collision. [AIEEE 2005] (a) \(\underline{v}\) (b) \(\sqrt{3} v\) (c) \(\frac{2}{\sqrt{3}} v\). (d) \(\frac{v}{\sqrt{3}}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.