/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 The magnetie flux linked with th... [FREE SOLUTION] | 91Ó°ÊÓ

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The magnetie flux linked with the coil varies with time as \(\phi=3 t^{2}+4 t+9\). The magnitude of the induced emf at 2 s is (a) \(9 \mathrm{~V}\) (b) \(16 \mathrm{~V}\) (c) \(3 \mathrm{~V}\) (d) \(4 \mathrm{~V}\)

Short Answer

Expert verified
The magnitude of the induced emf at 2 s is 16 V, option (b).

Step by step solution

01

Identify the Given Function

The expression for the magnetic flux linked with the coil is given as \( \phi(t) = 3t^2 + 4t + 9 \). You are interested in finding the induced electromotive force (emf) at \( t = 2 \) seconds.
02

Recall Faraday's Law

Faraday's Law states that the induced emf is equal to the negative rate of change of magnetic flux with respect to time. Mathematically, it is expressed as \( \varepsilon = - \frac{d\phi}{dt} \).
03

Differentiate the Magnetic Flux

To find the rate of change of flux, differentiate \( \phi(t) = 3t^2 + 4t + 9 \) with respect to \( t \).\[ \frac{d\phi}{dt} = \frac{d}{dt}(3t^2 + 4t + 9) = 6t + 4 \].
04

Calculate the Induced emf at 2s

Substitute \( t = 2 \) into the derivative to find the rate of change at that moment:\[ \frac{d\phi}{dt} \bigg|_{t=2} = 6(2) + 4 = 12 + 4 = 16 \].The induced emf is then \( \varepsilon = -16 \), but we are interested only in the magnitude.
05

Determine the Magnitude of emf

Since the problem asks for the magnitude of the induced emf, ignore the negative sign: \( |\varepsilon| = 16 \).
06

Identify the Correct Option

Given the magnitude of the induced emf is \( 16 \), the correct option from the choices provided is (b) \( 16 \mathrm{~V} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Faraday's Law
Faraday's Law is one of the fundamental principles explaining how electric currents can be generated by changing magnetic fields. It is at the heart of electromagnetic induction — a key process in many electrical systems such as transformers and generators.
When the magnetic environment of a circuit changes, it influences the circuit and an electromotive force (emf) is induced. The core idea is that a changing magnetic field over time will produce electricity. This is expressed mathematically by the formula:
\[ \varepsilon = - \frac{d\phi}{dt} \]
where \( \varepsilon \) is the induced emf, and \( \frac{d\phi}{dt} \) is the rate of change of the magnetic flux \( \phi \) with respect to time.
The negative sign is crucial because it indicates the direction of the induced emf which opposes the change in flux, as established by Lenz's Law. This means that the circuit will resist changes in its magnetic environment.
Magnetic Flux
Magnetic Flux quantifies the total magnetic field passing through a given area. It is a useful way to understand and calculate the influence of a magnetic field in electromagnetism.
Magnetic flux is denoted by the symbol \( \phi \) and is measured in Weber (Wb). It can be given by the formula:
\[ \phi = B \cdot A \cdot \cos(\theta) \]
where:
  • \( B \) is the magnetic field strength (in Tesla)
  • \( A \) is the area through which the field lines pass (in square meters)
  • \( \theta \) is the angle between the magnetic field lines and the perpendicular to the surface
In practical terms, whenever you change the magnetic field strength, the area, or the orientation of the circuit, you change the magnetic flux. As the exercise shows, if the magnetic flux changes with time, this will induce an emf according to Faraday's Law.
Differentiation
Differentiation is a mathematical technique used to determine the rate at which a quantity changes with respect to another quantity. In the context of the exercise, it is essential for calculating the rate of change of magnetic flux.
To find the induced emf, you differentiate the expression for magnetic flux, which is given as \( \phi(t) = 3t^2 + 4t + 9 \).
The differentiation process involves applying basic calculus rules:
\[ \frac{d\phi}{dt} = \frac{d}{dt}(3t^2 + 4t + 9) = 6t + 4 \]
This derivative \( 6t + 4 \) represents how the flux changes at any given moment \( t \). Evaluating this at \( t = 2 \) gives you \( 16 \). The differentiation allows you to pinpoint the exact rate of flux change, which directly leads to calculating the induced emf as per Faraday's Law.

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Most popular questions from this chapter

The vertical component of earth's magnetic field is zero at or the earth's magnetic field always has a vertical component except at the INCERT Exemplar] [a) Magnetic poles (b) Geographic poles (c) Every place (d) Magnetic equator

A circular coil of 16 turns and radius \(10 \mathrm{~cm}\) carrying a current of \(0.75\) A rests with its plane normal to an external field of magnitude \(5.0 \times 10^{-2} \mathrm{~T} .\) The coil is free to turn about an axis in its plane perpendicular to the field direction. When the coil is turned slightly and released, it oscillates about its stable equilibrium with a frequency of \(2.0 / \mathrm{s}\). What is the moment of inertia of the coil about its axis of rotation? (a) \(1.2 \times 10^{-4} \mathrm{~g}-\mathrm{cm}^{2}\) (b) \(3 \times 10^{-4} \mathrm{~kg}-\mathrm{m}^{2}\) (c) \(0.3 \times 10^{-4} \mathrm{~kg}-\mathrm{m}^{2}\) (d) \(1.2 \times 10^{-4} \mathrm{~kg}-\mathrm{m}^{2}\)

A bar magnet is placed north-south with its north pole due north. The points of zero magnetic field will be in which direction from centre of magnet (a) north and south (b) east and west (c) north-east and south-west (d) north-east and south-east

The points \(A\) and \(B\) are situated perpendicular to the axis of \(2 \mathrm{~cm}\) long bar magnet at large distances \(x\) and \(3 x\) from the centre on opposite sides. The ratio of magnetic fields at \(A\) and \(B\) will be approximately equal to (a) \(27: 1\) (b) \(1: 27\) (c) \(9: 1\) (d) \(1: 9\)

The earth's magnetic induction at a certain point is \(7 \times 10^{-5} \mathrm{Wbm}^{-2}\). This is to be annulled by the magnetic induction at the centre of a circular conducting loop of radius \(15 \mathrm{~cm}\). The required current in the loop is (a) \(0.56 \mathrm{~A}\) (b) \(5.6 \mathrm{~A}\) (c) \(0.28 \mathrm{~A}\) (d) \(2.8 \mathrm{~A}\)

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