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(a) Find \(\langle r\rangle\) and \(\left\langle r^{2}\right\rangle\) for an electron in the ground state of hydrogen. Express your answers in terms of the Bohr radius. (b) Find \(\langle x\rangle\) and \(\left\langle x^{2}\right\rangle\) for an electron in the ground state of hydrogen. Hint: This requires no new integration-note that \(r^{2}=x^{2}+y^{2}+z^{2},\) and exploit the symmetry of the ground state. (c) Find \(\left\langle x^{2}\right\rangle\) in the state \(n=2, \ell=1, m=1 .\) Hint: this state is not symmetrical in \(x, y, z .\) Use \(x=r \sin \theta \cos \phi\).

Short Answer

Expert verified
\(\langle r \rangle = \frac{3}{2}a_0\), \(\langle r^2 \rangle = 3a_0^2\); \(\langle x \rangle = 0\), \(\langle x^2 \rangle = a_0^2\) (ground state); \(\langle x^2 \rangle = \frac{5}{8}a_0^2\) (n=2, \(\ell=1, m=1\)).

Step by step solution

01

Express Hydrogen Ground State Wave Function

The ground state wave function for a hydrogen atom is given by \[ \psi_{1s}(r) = \frac{1}{\sqrt{\pi a_0^3}} e^{-r/a_0} \]where \(a_0\) is the Bohr radius.
02

Calculate Expected Value of r, \(\langle r \rangle\)

To find \(\langle r \rangle\), compute the integral:\[ \langle r \rangle = \int_0^{\infty} r \cdot 4\pi r^2 \left| \psi_{1s}(r) \right|^2 \, dr \]Plug in \(\psi_{1s}(r)\) and solve, which results in \(\langle r \rangle = \frac{3}{2}a_0\).
03

Calculate Expected Value of \(r^2\), \(\langle r^2 \rangle\)

Compute:\[ \langle r^2 \rangle = \int_0^{\infty} r^2 \cdot 4\pi r^2 \left| \psi_{1s}(r) \right|^2 \, dr \]With \(\psi_{1s}(r)\) substituted, solve to find \(\langle r^2 \rangle = 3a_0^2\).
04

Determine \(\langle x \rangle\)

Given the symmetry of the ground state, and that the expectation value of position components \(x, y, z\) in a symmetric state is zero:\[ \langle x \rangle = 0 \]
05

Calculate \(\langle x^2 \rangle\) in Ground State

Use symmetry and \(r^2 = x^2 + y^2 + z^2\), with \(\langle x^2 \rangle = \langle y^2 \rangle = \langle z^2 \rangle\) in the ground state:\[ \langle x^2 \rangle = \frac{1}{3} \langle r^2 \rangle = \frac{1}{3}(3a_0^2) = a_0^2 \]
06

Calculate \(\langle x^2 \rangle\) in \(n=2, \ell=1, m=1\) State

Start with \(x = r \sin \theta \cos \phi\), and express \(x^2\):\[ \langle x^2 \rangle = \langle r^2 \sin^2 \theta \cos^2 \phi \rangle \]For the \(n=2, \ell=1, m=1\) state, solve the integral of the corresponding wave function to get \(\langle x^2 \rangle = \frac{5}{8}a_0^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bohr radius
In atomic physics, the Bohr radius signifies the scale size of hydrogen atoms, specifically the average distance between the nucleus and the electron in the ground state of a hydrogen atom. The Bohr radius, denoted as \(a_0\), is a fundamental constant with a value approximately equal to 0.529 Ångströms, or \(5.29 \times 10^{-11} \ m\). It originates from the Bohr model of the atom, which Niels Bohr devised to explain the discrete energy levels of electrons in atoms.
In calculations involving hydrogen, the Bohr radius serves as a convenient unit of length. For example, when we calculate the average position of an electron, \(\langle r\rangle\), in the hydrogen atom, we find it to be \(\frac{3}{2}a_0\), demonstrating the meaningfulness of the Bohr radius in predicting electron behavior.
Wave function
The wave function is a fundamental concept in quantum mechanics. It provides a mathematical description of the quantum state of a particle, such as an electron in a hydrogen atom. For the ground state of a hydrogen atom, the wave function is denoted as \(\psi_{1s}(r)\) and is given by:
\[\psi_{1s}(r) = \frac{1}{\sqrt{\pi a_0^3}} e^{-r/a_0}\]
This equation highlights how the probability density for finding an electron at a specific point in space decreases exponentially with distance from the nucleus (ucleus at \(r = 0\)).
In quantum mechanics, the square of the wave function's magnitude, \(\left|\psi_{1s}(r)\right|^2\), represents the probability density of the electron's position. For the hydrogen atom, this function is spherically symmetric, meaning the probability of finding the electron depends only on the distance from the nucleus and not on the direction. This sphericity explains why, in the symmetrical ground state, average position values like \(\langle x\rangle\) result in zero.
Expected value
In quantum mechanics, the expected value—or expectation value—refers to the average outcome of a measurement on a quantum system. It is denoted using angle brackets. For instance, \(\langle r \rangle\) is the expected radial distance for an electron in an atom.
To calculate expected values, we use integrals that incorporate the wave function. These integrals take into account all possible states of the electron. For instance, for a hydrogen atom in its ground state, the expected value of \(r\), \(\langle r \rangle\), is:
\[\langle r \rangle = \int_0^{\infty} r \cdot 4\pi r^2 \left| \psi_{1s}(r) \right|^2 \, dr = \frac{3}{2} a_0\]
Similarly, the expected value of \(r^2\), \(\langle r^2 \rangle\), is \(3a_0^2\). These values give us insight into the most probable arrangement of the cloud of an electron, helping us understand the distribution of the electron around its nucleus.
Quantum mechanics
Quantum mechanics is the branch of physics that deals with phenomena at microscopic scales, like atoms and subatomic particles. Unlike classical physics, which relies on deterministic laws, quantum mechanics incorporates probability and uncertainty.
The hydrogen atom is a key system in quantum mechanics studies, as it provides simple yet profound insights into atomic structure. At the core of quantum theories about hydrogen is the Schrödinger equation, which describes the wave function of the system.
In quantum mechanics, the behavior and properties of particles such as electrons are described not just in terms of predictable paths, as in classical mechanics, but in terms of probabilities. This fundamental shift allows us to predict the likelihood of an electron's position or energy level, making quantum mechanics an essential framework for understanding the atomic and subatomic world. These concepts not only explain observed phenomena but also predict results in experiments with high accuracy.

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Most popular questions from this chapter

Calculate \((z \hat{H} z),\) in the ground state of hydrogen. Hint: This takes two pages and six integrals, or four lines and no integrals, depending on how you set it up. To do it the quick way, start by noting that \([z,[H, z]]=2 z H z-H z^{2}-z^{2} H^{25}\).

(a) Construct the wave function for hydrogen in the state \(n=4, \ell=3\), \(m=3 .\) Express your answer as a function of the spherical coordinates \(r\), \(\theta,\) and \(\phi\). (b) Find the expectation value of \(r\) in this state. (As always, look up any nontrivial integrals.) (c) If you could somehow measure the observable \(L_{x}^{2}+L_{y}^{2}\) on an atom in this state, what value (or values) could you get, and what is the probability of each?

Use separation of variables in cartesian coordinates to solve the infinite cubical well (or "particle in a box"): \(V(x, y, z)=\left\\{\begin{array}{ll}0, & x, y, z \text { all between } 0 \text { and } a; \\ \infty, & \text { otherwise .}\end{array}\right.\) (a) Find the stationary states, and the corresponding energies. (b) Call the distinct energies \(E_{1}, E_{2}, E_{3}, \ldots,\) in order of increasing energy. Find \(E_{1}, E_{2}, E_{3}, E_{4}, E_{5},\) and \(E_{6} .\) Determine their degeneracies (that is, the number of different states that share the same energy). Comment: In one dimension degenerate bound states do not occur (see Problem 2.44 ), but in three dimensions they are very common. (c) What is the degeneracy of \(E_{14}\), and why is this case interesting?

Starting from the Rodrigues formula, derive the orthonormality condition for Legendre polynomials: \(\int_{-1}^{1} P_{\ell}(x) P_{\ell^{\prime}}(x) d x=\left(\frac{2}{2 \ell+1}\right) \delta_{\ell \ell}\). Hint: Use integration by parts.

Determine the commutator of \(s^{2}\) with \(S_{z}^{(1)}\) (where \(\mathbf{S} \equiv \mathbf{S}^{(1)}+\mathbf{S}^{(2)}\)) Generalize your result to show that \(\left[S^{2}, \mathbf{S}^{(1)}\right]=2 i \hbar\left(\mathbf{S}^{(1)} \times \mathbf{S}^{(2)}\right)\). Comment: Because \(S_{z}^{(1)}\) does not commute with \(S^{2},\) we cannot hope to find states that are simultaneous eigenvectors of both. In order to form eigenstates of \(S^{2}\) we need linear combinations of eigenstates of \(S_{z}^{(1)} .\) This is precisely what the ClebschGordan coefficients (in Equation 4.183 ) do for us. On the other hand, it follows by obvious inference from Equation 4.185 that the \(\operatorname{sum} \mathbf{S}^{(1)}+\mathbf{S}^{(2)}\) does commute with \(\left.S^{2}, \text { which only confirms what we already knew (see Equation } 4.103 \text { ). }\right]\)

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