/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Starting from the Rodrigues form... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Starting from the Rodrigues formula, derive the orthonormality condition for Legendre polynomials: \(\int_{-1}^{1} P_{\ell}(x) P_{\ell^{\prime}}(x) d x=\left(\frac{2}{2 \ell+1}\right) \delta_{\ell \ell}\). Hint: Use integration by parts.

Short Answer

Expert verified
The orthonormality condition is derived using integration by parts and boundary conditions.

Step by step solution

01

Understand the Rodrigues formula

The Rodrigues formula for Legendre polynomials is given by: \[ P_\ell(x) = \frac{1}{2^\ell \ell!} \frac{d^\ell}{dx^\ell} (x^2 - 1)^\ell \]where \( \ell \) is a non-negative integer. This represents the \( \ell^{th} \) Legendre polynomial.
02

Integrate Using the Orthonormality Condition

We need to find: \[ \int_{-1}^{1} P_{\ell}(x) P_{\ell^{\prime}}(x) \, dx \]If \( \ell = \ell' \), the integral should equal \( \frac{2}{2\ell + 1} \), and zero otherwise due to orthonormality.
03

Apply Integration by Parts

Using the Rodrigues formula, express one of the Legendre polynomials' derivatives form. For integration by parts, consider:\[ u = P_\ell(x) \quad \text{and} \quad dv = P_{\ell'}(x) \, dx \]Then find \( du \) and \( v \) and apply parts accordingly.
04

Simplify Using Boundary Conditions

When applying integration by parts, the boundary terms at -1 and 1 tend to zero due to the properties of Legendre polynomials and their derivatives. Thus, \[ \left[ P_\ell(x) P_{\ell'}(x) \right]_{-1}^{1} = 0 \] becomes the simplification step.
05

Apply Orthonormality Property

As a property:\[ \int_{-1}^{1} P_\ell(x) P_{\ell'}(x) \, dx = 0 \quad \text{for} \; \ell eq \ell' \]takes effect unless \( \ell = \ell' \). When \( \ell = \ell' \), the integral becomes nonzero.
06

Integrate When \( \ell = \ell' \)

For the case where \( \ell = \ell' \), the integral becomes:\[ \int_{-1}^{1} P_\ell(x)^2 \, dx = \frac{2}{2\ell + 1} \]due to normalization, completing the ortho-normality condition.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rodrigues formula
The Rodrigues formula offers a systematic approach for generating Legendre polynomials, which are a specific type of polynomial used in a variety of problems, especially those related to physics and engineering. The formula for the Legendre polynomial of degree \( \ell \) is expressed as:
  • \[ P_\ell(x) = \frac{1}{2^\ell \ell!} \frac{d^\ell}{dx^\ell} (x^2 - 1)^\ell \]
This means that for any integer \( \ell \), you can obtain the \( \ell^{th} \) Legendre polynomial by differentiating the function \((x^2 - 1)^\ell\) \( \ell \) times.

These polynomials are crucial in solving problems with spherical symmetry, such as gravitational or electric fields around a spherical object. Understanding the Rodrigues formula is fundamental because it provides a direct and manageable way to calculate Legendre polynomials when needed.
orthonormality condition
The orthonormality condition is a special property of Legendre polynomials. This property is crucial because it implies that Legendre polynomials, when integrated over a specific range, behave like 'orthogonal' vectors. Mathematically, this is expressed as:
  • \[ \int_{-1}^{1} P_\ell(x) P_{\ell'}(x) \, dx = \left(\frac{2}{2 \ell + 1}\right) \delta_{\ell \ell'} \]
Here, \( \delta_{\ell \ell'} \) is the Kronecker delta function, which equals 1 when \( \ell = \ell' \) and 0 otherwise. This relationship shows that within the interval from -1 to 1, the integral of the product of two Legendre polynomials is zero if the polynomials are of different orders \( \ell \) and \( \ell' \).

The orthonormality condition is incredibly useful in applications such as solving differential equations where solutions can be expanded into series of orthogonal functions, simplifying the mathematics considerably.
integration by parts
Integration by parts is a vital method in calculus, often used to evaluate integrals that are not straightforward. For Legendre polynomials, integration by parts is particularly useful to prove the orthonormality condition, enabling the simplification of integrals involving these polynomials.

The technique is analogous to the product rule of differentiation and is expressed as:
  • \[ \int u \, dv = uv - \int v \, du \]
When applying this to Legendre polynomials, you typically choose \( u = P_\ell(x) \) and \( dv = P_{\ell'}(x) \, dx \). Then, you find \( du \) and \( v \), allowing you to reorganize the integral. This step transforms difficult integrals into more manageable ones. Boundary terms, like \( \left[ P_\ell(x) P_{\ell'}(x) \right]_{-1}^{1} \), often simplify to zero due to the properties of Legendre polynomials.

This process helps you confirm the orthonormality relation by ensuring that potential boundary contributions do not interfere unless \( \ell = \ell' \).

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use separation of variables in cartesian coordinates to solve the infinite cubical well (or "particle in a box"): \(V(x, y, z)=\left\\{\begin{array}{ll}0, & x, y, z \text { all between } 0 \text { and } a; \\ \infty, & \text { otherwise .}\end{array}\right.\) (a) Find the stationary states, and the corresponding energies. (b) Call the distinct energies \(E_{1}, E_{2}, E_{3}, \ldots,\) in order of increasing energy. Find \(E_{1}, E_{2}, E_{3}, E_{4}, E_{5},\) and \(E_{6} .\) Determine their degeneracies (that is, the number of different states that share the same energy). Comment: In one dimension degenerate bound states do not occur (see Problem 2.44 ), but in three dimensions they are very common. (c) What is the degeneracy of \(E_{14}\), and why is this case interesting?

Calculate \((z \hat{H} z),\) in the ground state of hydrogen. Hint: This takes two pages and six integrals, or four lines and no integrals, depending on how you set it up. To do it the quick way, start by noting that \([z,[H, z]]=2 z H z-H z^{2}-z^{2} H^{25}\).

According to the Rydberg formula (Equation 4.93 ) the wavelength of a line in the hydrogen spectrum is determined by the principal quantum numbers of the initial and final states. Find two distinct pairs \(\left\\{n_{i}, n_{f}\right\\}\) that yield the same \(\lambda\). For example, \(\\{6851,6409\\}\) and \(\\{15283,11687\\}\) will do it, but you're not allowed to use those!

If the electron were a classical solid sphere, with radius \(r_{c}=\frac{e^{2}}{4 \pi \epsilon_{0} m c^{2}}\), (the so-called classical electron radius, obtained by assuming the electron's mass is attributable to energy stored in its electric field, via the Einstein formula \(\left.E=m c^{2}\right),\) and its angular momentum is \((1 / 2) \hbar,\) then how fast \((\text { in } \mathrm{m} / \mathrm{s})\) would a point on the "equator" be moving? Does this model make sense? (Actually, the radius of the electron is known experimentally to be much less than \(r_{c},\) but this only makes matters worse.) \(^{39}\)

A hydrogen atom starts out in the following linear combination of the stationary states \(n=2, \ell=1, m=1\) and \(n=2, \ell=1, m=-1\) \(\Psi(\mathbf{r}, 0)=\frac{1}{\sqrt{2}}\left(\psi_{211}+\psi_{21-1}\right)\) (a) Construct \(\Psi(\mathbf{r}, t) .\) Simplify it as much as you can. (b) Find the expectation value of the potential energy, \(\langle V\rangle\). (Does it depend on \(t ?\) Give both the formula and the actual number, in electron volts.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.