Chapter 2: Problem 34
Consider the "step" potential: 53 \(V(x)=\left\\{\begin{array}{ll}0, & x \leq 0
\\\ V_{0}, & x>0\end{array}\right.\)
(a) Calculate the reflection coefficient, for the case \(E
Short Answer
Step by step solution
Understand the potentials
Solve Schrödinger Equation for x ≤ 0
Solve Schrödinger Equation for x > 0, when E < V0
Boundary Conditions at x = 0, when E < V0
Calculate Reflection Coefficient R for E < V0
Solve Schrödinger Equation for x > 0, when E > V0
Boundary Conditions at x = 0, when E > V0
Calculate Reflection Coefficient R for E > V0
Derive the Transmission Coefficient T as a function of F and A
Calculate T for E > V0 and verify T + R = 1
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Step Potential
- For \( x \leq 0 \), the potential \( V(x) = 0 \)
- For \( x > 0 \), the potential jumps to \( V_0 \)
Understanding the step potential is essential, as it sets up scenarios where reflection and transmission of particles occur, much like waves at a boundary. This model is key to exploring more complex potential forms and is fundamental in quantum barriers and tunneling topics.
Schrödinger Equation Solutions
**Region 1: \( x \leq 0 \) (\( V(x) = 0 \))**
In this region, the Schrödinger Equation simplifies to:
\[\frac{d^2 \psi}{dx^2} + \frac{2mE}{\hbar^2}\psi = 0\]
The wave function solution in this case is a combination of incoming and reflected waves:
\[\psi_1(x) = Ae^{ik_1x} + Be^{-ik_1x}, \]
where \( k_1 = \frac{\sqrt{2mE}}{\hbar} \).
**Region 2: \( x > 0 \)**
*For \( E < V_0 \):*
The Schrödinger Equation becomes
- \[\frac{d^2 \psi}{dx^2} - \frac{2m(V_0 - E)}{\hbar^2}\psi = 0\]
- Leading to an exponentially decaying wave function as
\[\psi_2(x) = Ce^{-\kappa x},\]
with \( \kappa = \frac{\sqrt{2m(V_0 - E)}}{\hbar} \).
*For \( E > V_0 \):*
The equation becomes
\[\frac{d^2 \psi}{dx^2} + \frac{2m(E-V_0)}{\hbar^2}\psi = 0,\]
yielding a traveling wave solution
\[\psi_2(x) = De^{ik_2x},\]
where \( k_2 = \frac{\sqrt{2m(E-V_0)}}{\hbar} \).
These solutions encapsulate the possibility of different particle behaviors, such as reflection and passing through potential barriers.
Quantum Mechanics Boundary Conditions
To solve for actual behavior at boundaries:
- Wave functions must be continuous across regions.
- Wave function derivatives should also be continuous.
**For \( E < V_0 \) at \( x = 0 \):**
- \( A + B = C \),
- \( ik_1A - ik_1B = -\kappa C \).
**For \( E > V_0 \) at \( x = 0 \):**
- \( A + B = D \),
- \( ik_1A - ik_1B = ik_2D \).
Total Internal Reflection
**Reflection Coefficient (\( R \))**
For \( E < V_0 \), calculations demonstrate that the reflection coefficient \( R \) equals 1. This implies:
- All incident waves are reflected back.
- No transmission occurs beyond the step.
**Moving Beyond Total Reflection:**
For \( E > V_0 \), some partial transmission occurs, and \( R \) is given by
\[R = \left(\frac{k_1 - k_2}{k_1 + k_2}\right)^2,\]
noting the balance of \( T+R=1 \) ensuring conservation of probability. This showcases how energy influences particle behavior across potential regions.