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In the ground state of the harmonic oscillator, what is the probability (correct to three significant digits) of finding the particle outside the classically allowed region? Hint: Classically, the energy of an oscillator is \(E=(1 / 2) k a^{2}=(1 / 2) m \omega^{2} a^{2},\) where \(a\) is the amplitude. So the "classically allowed region" for an oscillator of energy \(E\) extends from \(-\sqrt{2 E / m \omega^{2}}\) to \(+\sqrt{2 E / m \omega^{2}} .\) Look in a math table under "Normal Distribution" or "Error Function" for the numerical value of the integral, or evaluate it by computer.

Short Answer

Expert verified
The probability is approximately 0.317.

Step by step solution

01

Understanding the Classically Allowed Region

The classically allowed region for a harmonic oscillator extends from \(-\sqrt{\frac{2E}{m\omega^2}}\) to \(+\sqrt{\frac{2E}{m\omega^2}}\). In the context of the ground state, the energy is given by \(E = \frac{1}{2} \hbar \omega\). Thus, the classically allowed region is \(\left(- \sqrt{\frac{\hbar}{m \omega}}, \sqrt{\frac{\hbar}{m \omega}}\right)\).
02

Expressing the Probability Outside this Region

The probability of finding the particle outside the classically allowed region involves calculating the wave function's squared modulus beyond this interval. For a simple harmonic oscillator, outside the region \(egin{-a}to{a}\), this probability translates to \(P(x < -a \text{ or } x > a)\).
03

Simplify the Probability Expression

In quantum mechanics, the ground state wave function for a harmonic oscillator is \(\psi(x) = \left(\frac{m\omega}{\pi\hbar}\right)^{1/4} e^{-\frac{m\omega x^2}{2\hbar}}\).We are interested in \(\int_{-\infty}^{-a} |\psi(x)|^2 \, dx + \int_{a}^{\infty} |\psi(x)|^2 \, dx\), which is given by the complimentary error function, \\(Q(x) = \text{erfc}\left(\sqrt\frac{m\omega}{\hbar} a \right)\).
04

Calculating the Uncertainty and Using Erf

The error function, \(\text{erf}(x)\), needs to be evaluated. For \(\left(x = a \cdot \sqrt{m\omega/\hbar}\right)\) \(= \sqrt{\frac{\hbar/2}{\hbar}} = \sqrt{1/2}\). From error function tables, find that \(\text{erf}(x=0.707)\approx 0.6826.\) Hence, \(\text{erfc}(x=0.707)=1-\text{erf}(x)\approx 0.317\).
05

Conclusion on the Probability Outside the Region

Finally, the probability of being outside the classically allowed region (outside \(-a\) to \(+a\) is the same as \(0.317\). We round off to three significant figures, giving us \(0.317\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Function
In the study of quantum mechanics, the wave function is a fundamental concept. It provides a complete description of the quantum state of a system. For the quantum harmonic oscillator, the wave function in its simplest form is given by:
  • \[ \psi(x) = \left( \frac{m\omega}{\pi\hbar} \right)^{1/4} e^{-\frac{m\omega x^2}{2\hbar}} \]
This equation represents the ground state of the harmonic oscillator. The wave function, \(\psi(x)\), contains all the information about the probability amplitude of a particle's position in space. The square of the wave function's magnitude at a point, \(|\psi(x)|^2\), gives us the probability density at that point. Thus, by examining the wave function, one can determine where a particle is most likely to be found. It is crucial in predicting and understanding the behavior of quantum systems.
Classically Allowed Region
In classical mechanics, the motion of a harmonic oscillator can be confined to a region, known as the classically allowed region. This is the range where the potential energy does not exceed the total mechanical energy. Mathematically, it's expressed with respect to the total energy \(E\) and is deduced from:
  • Energy formula: \(E = \frac{1}{2} m \omega^2 a^2\)
For a ground state, the classically allowed region extends between \(-\sqrt{\frac{2E}{m\omega^2}}\) and \(+\sqrt{\frac{2E}{m\omega^2}}\). This region represents where a particle 'should' be found, based on familiar classical interpretations. However, quantum mechanics reveals that the particle can be found outside this range due to its wave-like properties. Identifying the classically allowed region helps differentiate between classical and quantum behavior, particularly in calculating probabilities of a particle's location outside this region.
Error Function
The error function, denoted as \(\text{erf}(x)\), is an important mathematical tool used in probability and statistics, as well as in quantum mechanics to evaluate integrals that involve Gaussian distributions. For wave functions, it helps compute probabilities over specific intervals:
  • Defined as: \(\text{erf}(x) = \frac{2}{\sqrt{\pi}} \int_0^x e^{-t^2} \, dt\)
  • Complementary error function: \(\text{erfc}(x) = 1 - \text{erf}(x)\)
In the context of the quantum harmonic oscillator, the error function helps determine the likelihood of a particle being found outside the classically allowed region. By integrating the probability density function over specified limits, the error function provides a straightforward way to calculate such probabilities. This is essential for determining behavior that diverges from classical predictions.
Ground State
The ground state of a quantum harmonic oscillator represents its lowest energy state. It is characterized by certain properties unique to quantum systems. In this state, the energy level is at its minimum, meaning:
  • Energy: \(E = \frac{1}{2} \hbar \omega\)
The corresponding wave function takes on a Gaussian form, which is significant in that it suggests that the particle's position is most likely near the center or at rest. In classical systems, a particle that is at its lowest energy is expected to remain motionless. However, in quantum systems, there is unavoidable uncertainty due to Heisenberg's Uncertainty Principle. Thus, even in the ground state, the particle exhibits zero-point energy and exhibits a non-zero probability of tunneling outside the classical region.
Probability Calculation
Probability calculations in quantum mechanics differ from classical probabilities as they take into account wave nature and uncertainty. For a particle in a harmonic oscillator, calculating probability involves:
  • Wave function: \(\psi(x) = \left( \frac{m\omega}{\pi\hbar} \right)^{1/4} e^{-\frac{m\omega x^2}{2\hbar}}\)
  • Finding probabilities: Integrate \(|\psi(x)|^2\) over domains of interest
To find the probability that a particle exists outside the classically allowed region, split the integral into two regions: \(x < -a\) and \(x > a\). This, using the complementary error function \(\text{erfc}(x)\), simplifies this calculation by directly providing the probability outside the bounds. The outcome often reveals values such as \(0.317\), indicating a tangible probability under quantum mechanics for a particle to exist outside classically presumed boundaries. This reflects how quantum mechanics provides a richer, albeit less intuitive, understanding of particle positions.

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