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Show thatΘ=AIn[tan(θ2)]satisfies the θequation (Equation 4.25), for l = m = 0. This is the unacceptable "second solution" -- whats wrong with it?

Short Answer

Expert verified

Θθ=AIn[tanθ2]does satisfy the equation but this is the unacceptable second solution since Θblows up at θ=0and atθ=π

Step by step solution

01

Define the Schrödinger equation

A differential equation describes matter in quantum mechanics in terms of the wave-like properties of particles in a field. Its answer is related to a particle's probability density in space and time.

02

Calculation

We need to show that,

Θθ=AIn[tanθ2]

Satisfies the equation

sinθddθ(sinθdΘdθ+[II+1sin2θ-m2]Θ=0

So now take the derivative then we get,

dΘdθ=Atan(θ2)12sec2(θ2)dΘdθ=A21sin(θ2)cos(θ2)=Asinθ

Therefore,

ddθ(sinθdΘdθ)=ddθA=0

Then, we get,

role="math" localid="1656064432888" Θ0=AIn0=A-∞Θπ=AIn(tanπ2)=AIn-∞=A∞

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Most popular questions from this chapter

Construct the spin matrices(Sx,Sy a²Ô»åSz) , for a particle of spin 1. Hint: How many eigenstates ofSz are there? Determine the action of Sz, S+, and S−on each of these states. Follow the procedure used in the text for spin 1/2.

Determine the commutator of S2withSZ(1)(whereS≡S(1)+S(2)) Generalize your result to show that

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