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The raising and lowering operators change the value of m by one unit:

Lflm=(Alm)flm+1, (4.120).

Where Almare constant. Question: What is Alm, if the Eigen functions are to be normalized? Hint: First show thatLis the Hermitian conjugate of L(Since LxandLyare observables, you may assume they are Hermitian鈥ut prove it if you like); then use Equation 4.112.

Short Answer

Expert verified

If the Eigen functions are to be normalized, they are upper and lower signs.

Step by step solution

01

Given.

The raising and lowering operators are:

L+flm=(Alm)flm+1,L-flm=(Blm)flm-1,

02

Eigen functions to be normalized

We start solving the problem by taking the inner product between a hydro genic set acted upon Land Las following:

Alm=l(l+1)-m(m+1)=l(l+1)-m(m+1),Blm=l(l+1)-m(m+1)=l(l+1)-m(m+1),L2=LL+Lz2魔尝z(4.112).

Note what happens at the top and bottom of the ladder (i.e. when you apply L+L+tofllorL-tofl-lNow,usingEq.4.112,inthefromLL=L2-Lz2魔尝zLL2=LL+Lz2魔尝zL2=L4.112.

flmlLmLflm=flmlL2-Lz2mhLzflm=flml[h2ll+l-h2m2mh2m]flm=h2ll+1-mm1flmlflm=h2ll+1-mm1=LflmlLflmUppersigns:2ll+1-mm+1=L+flmlL+flm=Almflm+1lAlmflm+1=Alm2Alm=ll+1-mm+1Lowersigns:2ll+1-mM-1=L-flmlL-flm=Blmflm-1lBlmflm-1=Blm2

At the top of the ladderm=lwe get All=0wegetAll=0, so there is no higher rung; at the bottom of the ladder m=l we getBl-l=0 , so there is no lower rung.

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Most popular questions from this chapter

Consider the earth鈥搒un system as a gravitational analog to the hydrogen atom.

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(c) Show thatlocalid="1656131424007" 11>andlocalid="1656131406083" 1-1>(Equation4.177) are eigenstates ofS2, with the appropriate eigenvalue

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