91Ó°ÊÓ

To prove, $\mathrm{A}×(\mathrm{B}×\mathrm{C})+\mathrm{B}×(\mathrm{C}×\mathrm{A})+\mathrm{C}×(\mathrm{A}×\mathrm{B})=0$, firstly evaluate its left side, ,and compare the result with 0.

The left side of the equation is $\mathrm{A}×(\mathrm{B}×\mathrm{C})+\mathrm{B}×(\mathrm{C}×\mathrm{A})+\mathrm{C}×(\mathrm{A}×\mathrm{B})$, on using BAC-CAB rule, it is obtained as,

$$\begin{gathered} \mathrm{A}×(\mathrm{B}×\mathrm{C})+\mathrm{B}×(\mathrm{C}×\mathrm{A})+\mathrm{C}×(\mathrm{A}×\mathrm{B})=\left[\begin{array}{c}B\left(A·C\right)-C\left(A·B\right)+C\left(B·A\right)\\ -A\left(B·C\right)+A\left(B·C\right)-B\left(A·C\right)\end{array}\right] \\ =0 \end{gathered}$$

Thus, it is proved that LHS=RHS.

The cross product $\mathrm{A}×\mathrm{B}$is equal to $-\left(\mathrm{B}×\mathrm{A}\right)$. Thus, the given condition can rewritten as $\mathrm{A}×\left(\mathrm{B}×\mathrm{C}\right)=-\mathrm{C}\left(\mathrm{A}×\mathrm{B}\right)$. On using BAC-CAB rule, in $\mathrm{A}×\left(\mathrm{B}×\mathrm{C}\right)=-\mathrm{C}\left(\mathrm{A}×\mathrm{B}\right)$, the result is obtained as follows,

$$\begin{gathered} \mathrm{B}\left(\mathrm{A}·\mathrm{C}\right)-\mathrm{C}\left(\mathrm{A}·\mathrm{B}\right)=-\left[\mathrm{A}\left(\mathrm{C}·\mathrm{B}\right)-\mathrm{B}\left(\mathrm{C}·\mathrm{A}\right)\right] \\ \mathrm{B}\left(\mathrm{A}·\mathrm{C}\right)-\mathrm{C}\left(\mathrm{A}·\mathrm{B}\right)=-\left[\mathrm{A}\left(\mathrm{B}·\mathrm{C}\right)-\mathrm{B}\left(\mathrm{C}·\mathrm{A}\right)\right] \\ \mathrm{B}\left(\mathrm{A}·\mathrm{C}\right)-\mathrm{C}\left(\mathrm{A}·\mathrm{B}\right)+\mathrm{A}\left(\mathrm{B}·\mathrm{C}\right)-\mathrm{B}\left(\mathrm{A}·\mathrm{C}\right)=0 \\ -\mathrm{C}\left(\mathrm{A}·\mathrm{B}\right)+\mathrm{A}\left(\mathrm{B}·\mathrm{C}\right)=0 \end{gathered}$$

Rewrite as,

role="math" localid="1657350048596" $$\begin{gathered} -\left[\mathrm{C}\left(\mathrm{A}·\mathrm{B}\right)-\mathrm{A}\left(\mathrm{B}·\mathrm{C}\right)\right]=0 \\ -\mathrm{B}×\left(\mathrm{C}×\mathrm{A}\right)=0 \end{gathered}$$

If the two vectors are parallel or anti parallel with each other , then their cross product is zero. Thus the given condition is possible only when Bis either parallel or anti parallel to role="math" localid="1657350031823" $\left(\mathrm{C}×\mathrm{A}\right)$.