91Ó°ÊÓ

The given data is listed below as:

• The uniform magnetic field of the wire loop is,$B$
• The current carried by the loop is,$I$
• The chord subtended by the loop is,$\mathrm{Ó\neg }$

The magnetic field is described as the region around a particular magnet. The magnetic field is also beneficial for understanding distribution of magnetic force around a particular magnetic material.

The equation of the net magnetic force on the loop is expressed as:

$F=I∫\left(dI×B\right)$

Here,$I$is current,$dI$is the increase in the length and$B$is the uniform magnetic field.

As the uniform magnetic field is constant, then the equation of the net magnetic force can be expressed as:

$F=IB∫\left(dI\right)$ …(¾±)

The entering and the leaving point of the wire inside the magnetic field is same. So, the chord subtended by the loop and the uniform magnetic field are perpendicular to each other. Hence, the equation of the integration of the increase in the length can be expressed as:

$∫\left(dI\right)=\mathrm{Ó\neg }$

Here,$\mathrm{Ó\neg }$ is the chord subtended by the loop.

Substitute the above equation in equation (i).

$F=IB\mathrm{Ó\neg }$

Thus, the net magnetic force on the loop is $F=IB\mathrm{Ó\neg }$.

The force acts in the direction perpendicular to the chord subtended by the loop.