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Calculate∇×Edirectly from Eq. 2.8, by the method of Sect. 2.2.2. Refer to Prob. 1.63 if you get stuck.

Short Answer

Expert verified

The required value is∇×E(r)=0

Step by step solution

01

Determine the expression for the electric field in the two sphere.

Write the formula for the electric field of the volume charge.

Er=14πε0∫ÒÏr'r2r¯dT'

Write the curl of the above function as,

∇×Er=14πε0∫∆×r¯r2r'ÒÏdT' ….. (1)

Here, ε0is the permittivity of the free space and ÒÏis the charge density.

02

Determine the value of  ∆×(r¯)r2.  

Solve for ∆×r¯r2as,

localid="1655897481663" ∆×r¯r2=1r2∂∂rr¯+1rsinθ∂∂ϕϕ¯×rnϕ=r¯θ^ϕ^1r2∂∂r1rsinθ∂∂θ1rsinθ∂∂ϕr200=r^0-0-θ^0-1rsinθ∂∂ϕr2+ϕ^0-1rsinθ∂∂ϕr2=0

Substitute 0 for ∇×(r^)r2in the equation ∇×Er=14pε0∫∇×(r^)r2r'pdτ.

∇×Er=14pε0(0)=0

Therefore, the required value is ∇×E(r)=0.

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