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Two concentric metal spherical shells, of radius a and b, respectively, are separated by weakly conducting material of conductivity(Fig. 7 .4a).

(a) If they are maintained at a potential difference V, what current flows from one to the other?

(b) What is the resistance between the shells?

(c) Notice that if b>>a the outer radius (b) is irrelevant. How do you account for that? Exploit this observation to determine the current flowing between two metal spheres, each of radius a, immersed deep in the sea and held quite far apart (Fig. 7 .4b ), if the potential difference between them is V. (This arrangement can be used to measure the conductivity of sea water.)

Short Answer

Expert verified

(a) The expression for the current isI=4(VaVb)(1a1b) .

(b) The resistance between the shells is14(1a1b) .

(c) The expression for the current between the two sphere is2Va .

Step by step solution

01

Determine the formula for the electric field as 

Consider the formula for the electric field

E=140Qr2

Here0, is the permittivity of the free space,Q is the charge andr is the distance between the sphere.

Consider the expression for the current is

I=VR

02

(a) Determine the value of the current flowing

Determine the electric filed between concentric metal spheres.

E=140Qr2

If the voltage potential difference is Vin the concentric spheres having radius aand b.

Write the expression for the voltage difference as

VaVb=baQ401r2dr=Q40ba1r2dr=Q40(1a1b) 鈥.. (1)

Consider the formula for the electric current in terms of the electric current density is

I=Eda=Q0

From equation (1) rewrite the expression for current as

.I=40(VaVb)0(1a1b)I=4(VaVb)(1a1b)

Therefore, the expression for the current isI=4(VaVb)(1a1b) .

03

(b) Determine the resistance between the shells

Consider the formula for the resistance as

R=VI

Rewrite the expression for the resistance in terms of the voltage difference as

R=VaVb4(VaVb)(1a1b)=14(1a1b)

04

(c) Determine the current between the two spheres

Consider that b>>>a here, on negating athe sphere feel current by the sphere b on the basis of the difference between both the sphere. The expression is鈥

R=14a

Since, the resistance is due to the inner sphere, the successive shells have less contribution in the current because of the small cross sectional area.

Write the expression for the two submerged sphere as

R=24a=12a

From the general expression for the resistance solve as

R=VII=V12aI=2Va

Therefore, the expression for the current between the two sphere is 2Va.

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Most popular questions from this chapter

Problem 7.61 The magnetic field of an infinite straight wire carrying a steady current I can be obtained from the displacement current term in the Ampere/Maxwell law, as follows: Picture the current as consisting of a uniform line charge moving along the z axis at speed v (so that I=位惫), with a tiny gap of length E , which reaches the origin at time t=0. In the next instant (up to t=E/v) there is no real current passing through a circular Amperian loop in the xy plane, but there is a displacement current, due to the "missing" charge in the gap.

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