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When you polarize a neutral dielectric, the charge moves a bit, but the total remains zero. This fact should be reflected in the bound charges σb and ÒÏb· Prove from Eqs. 4.11 and 4.12 that the total bound charge vanishes.

Short Answer

Expert verified

The value of total charge of a piece of neutral dielectricQtotal is 0.

Step by step solution

01

Write the given data from the question

Consider thereflected in the bound charges σband ÒÏb·

Consider when you polarize a neutral dielectric, the charge moves a bit, but the total remains zero.

02

Determine the formula of total charge of a piece of neutral dielectric Qtotal.

Write the formula of total charge of a piece of neutral dielectric Qtotal.

Qtotal=∮SσbdS+∫νÒÏbdÏ„ …… (1)

Here, σb and ÒÏb are the reflected in the bound charges.

03

 Determine the value of total charge of a piece of neutral dielectric Qtotal.

Determine thetotal charge of a piece of neutral dielectric.

SubstituteP→⋅n^ for σand∇⋅P→ forÒÏ into equation (1).

Qtotal=∮SσdS+∫ν∇⋅P→dτ

However, according to divergence law, the two terms are equivalent and cancel one another out.

Qtotal=0

Therefore, the value of total charge of a piece of neutral dielectricQtotal is 0.

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