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Show that the energy of an ideal dipole p in an electric field E isgiven by

U=−p⋅E∈

Short Answer

Expert verified

Thepotential energy for the dipole moment is−p⋅E .

Step by step solution

01

Determine the formulas

Consider the formula for the torque on the dipole moment as

Ï„=±è·¡²õ¾±²Ôθ

Here, pis the dipole moment and E is the electric field.

02

Determine the formula for the energy of the dipole moment 

Consider the formula for work done in the rotating dipole moment as:

dw=τdθ

Substitute the values and solve as

dw=pEsinθdθw=∫a1a2pEsinθdθw=pE(cosθ1−cosθ2)

Consider the change in the potential for the two dipole positions and the corresponding working done as

w=U(θ2)−U(θ1)=−pE(cosθ2−θ1)=−pEcosθ=−p⋅E

Therefore, the potential energy for the dipole moment is −p⋅E.

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Most popular questions from this chapter

A hydrogen atom (with the Bohr radius of half an angstrom) is situated

between two metal plates 1 mm apart, which are connected to opposite terminals of a 500 V battery. What fraction of the atomic radius does the separation distance d amount to, roughly? Estimate the voltage you would need with this apparatus to ionize the atom. [Use the value of in Table 4.1. Moral:The displacements we're talking about are minute,even on an atomic scale.]

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The Clausius-Mossotti equation (Prob. 4.41) tells you how to calculatethe susceptibility of a nonpolar substance, in terms of the atomic polariz-ability. The Langevin equation tells you how to calculate the susceptibility of apolar substance, in terms of the permanent molecular dipole moment p. Here's howit goes:

(a) The energy of a dipole in an external field E isu=-p··¡³¦´Ç²õθ

(Eq. 4.6), whereθ is the usual polar angle, if we orient the z axis along E.

Statistical mechanics says that for a material in equilibrium at absolute temperature

T, the probability of a given molecule having energy u is proportional to

the Boltzmann factor,

exp(-u/kT)

The average energy of the dipoles is therefore

<u>=∫ue-(u/kt)»åΩ∫e-(u/kT)»åΩ

where »åΩ=²õ¾±²Ôθ»åθ»åÏ•, and the integration is over all orientations θ:0→π;Ï•:0→2Ï€Use this to show that the polarization of a substance

containing N molecules per unit volume is

P=Np[cothpE/kT-kT/pE] (4.73)

That's the Langevin formula. Sketch as a function ofPE/KT .

(b) Notice that for large fields/low temperatures, virtually all the molecules arelined up, and the material is nonlinear. Ordinarily, however, kT is much greaterthan p E. Show that in this regime the material is linear, and calculate its susceptibility,in terms of N, p, T, and k. Compute the susceptibility of water at 20°C,and compare the experimental value in Table 4.2. (The dipole moment of wateris 6.1×10-30C·m) This is rather far off, because we have again neglected thedistinction between E and Eelse· The agreement is better in low-density gases,for which the difference between E and Eelse is negligible. Try it for water vapor

at 100°C and 1 atm.

A point charge qis situated a large distance rfrom a neutral atom of

polarizability α.Find the force of attraction between them.

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