/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Runner \(A\) is initially \(6.0 ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Runner \(A\) is initially \(6.0 \mathrm{km}\) west of a flagpole and is running with a constant velocity of \(9.0 \mathrm{km} / \mathrm{h}\) due east. Runner \(\mathrm{B}\) is initially \(5.0 \mathrm{km}\) east of the flagpole and is running with a constant velocity of \(8.0 \mathrm{km} / \mathrm{h}\) due west. What will be the distance of the two runners from the flagpole when their paths cross? (It is not necessary to convert your answer from kilometers to meters for this problem. You may leave it in kilometers.)

Short Answer

Expert verified
When their paths cross, both runners will be 15 km from the flagpole.

Step by step solution

01

Understand the given problem

Runner A is starting from 6.0 km west of a flagpole and is running towards east at a speed of 9.0 km/h. Runner B starts at a point 5.0 km east of the flagpole and is running westwards at 8.0 km/h.
02

Write the equation of motion for Runner A

The equation of motion for Runner A, considering the west as the positive direction, will be: Distance of A = Initial position of A + velocity of A * time = 6 km + 9 km/h * t.
03

Write the equation of motion for Runner B

The equation of motion for Runner B, considering the east as the positive direction, will be: Distance of B = Initial position of B + velocity of B * time = 5 km + 8 km/h * t.
04

Set the distances travelled by both runners equal to each other

Since they are crossing each other's paths, the distances they have travelled from their starting points are equal. Hence, we equate the distances covered by runner A and runner B from the flagpole. So, 6 + 9t = 5 + 8t.
05

Solve for Time

By simplifying the equation from step 4, we find t = 1 hour.
06

Find the distance from flagpole

Now, substitute t = 1 hour into the equation for distance from the flagpole for either runner (it doesn't matter which one since they're at the same place). Let's use Runner A's: Distance = 6 km + (9 km/h * 1 hr) = 15 km.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Velocity
Relative velocity is a concept that describes the velocity of an object as observed from another object's frame of reference. In this exercise, we consider the velocities of Runner A and Runner B with respect to each other, as well as with respect to the flagpole.

Both runners are moving towards each other from opposite directions. Runner A is headed east, while Runner B is heading west. Therefore, their relative velocities add up because they are approaching each other, not moving away.

  • Runner A's velocity is 9.0 km/h east.
  • Runner B's velocity is -8.0 km/h east (or 8.0 km/h west).
  • The relative velocity between them is thus 9 + 8 = 17 km/h.
Understanding relative velocity helps to predict the rate at which two objects will meet, which is crucial in solving this problem.
Motion Equations
Motion equations are essential tools in kinematics, allowing us to describe object motion quantitatively. For Runner A and Runner B, we use these equations to track their movement over time. In this exercise, the motion equations are used to determine when the two runners will cross paths.

For Runner A, moving towards the east and starting 6 km to the west, the equation of motion is:
\[\text{Distance of A} = 6 + 9t\]
For Runner B, moving west and starting 5 km to the east, the equation of motion is:
\[\text{Distance of B} = 5 + 8t\]
Here:
  • "6" is the initial distance of Runner A from the flagpole, westward.
  • "5" is the initial distance of Runner B from the flagpole, eastward.
  • "t" represents the time in hours.
  • "9t" and "8t" are the distances traveled after time "t" for Runners A and B respectively.
These equations allow us to calculate exact positions at any time "t", enabling us to find when the runners' positions are identical - meaning their paths cross.
Problem-Solving
Problem-solving in physics involves breaking down complex situations into simpler, more manageable parts. In our exercise, we have approached this systematically by using equations of motion and concepts of relative velocity. Here's how we solved the problem:

1. **Understanding the Problem**: We noted both runners' starting positions and velocities.2. **Setting Up Equations**: Using motion equations, we defined how far each runner would be from the flagpole over time.3. **Equating Distances**: To find when they cross paths, we needed the distances from the flagpole to be equal, setting the equations of motion equal to one another.
\[ 6 + 9t = 5 + 8t \]

4. **Solving for Time**: By simplifying, we found that they cross after 1 hour.

5. **Determining Cross Point**: Calculating either runner's distance from the flagpole at this time involves subbing the time back into an equation of motion.
The runners cross 15 km from the flagpole. This structured problem-solving approach helps in understanding not just how but why these calculations yield the solution. Always break tasks into smaller parts, solve systematically, and double-check your steps.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two cars are traveling along a straight line in the same direction, the lead car at \(25 \mathrm{m} / \mathrm{s}\) and the other car at \(35 \mathrm{m} / \mathrm{s}\). At the moment the cars are \(45 \mathrm{m}\) apart, the lead driver applies the brakes, causing the car to have an acceleration of \(-2.0 \mathrm{m} / \mathrm{s}^{2}\) a. How long does it take for the lead car to stop? b. Assume that the driver of the chasing car applies the brakes at the same time as the driver of the lead car. What must the chasing car's minimum negative acceleration be to avoid hitting the lead car? c. How long does it take the chasing car to stop?

See Sample Problem A. A school bus takes \(0.530 \mathrm{h}\) to reach the school from your house. If the average velocity of the bus is \(19.0 \mathrm{km} / \mathrm{h}\) to the east, what is the displacement?

One swimmer in a relay race has a 0.50 s lead and is swimming at a constant speed of \(4.00 \mathrm{m} / \mathrm{s}\). The swimmer has \(20.0 \mathrm{m}\) to swim before reaching the end of the pool. A second swimmer moves in the same direction as the leader. What constant speed must the second swimmer have in order to catch up to the leader at the end of the pool?

If a car is traveling eastward, can its acceleration be westward? Explain your answer, and use an example in your explanation.

A train travels between stations 1 and \(2,\) as shown below. The engineer of the train is instructed to start from rest at station 1 and accelerate uniformly between points \(A\) and \(B\), then coast with a uniform velocity between points \(B\) and \(C\), and finally accelerate uniformly between points \(C\) and \(D\) until the train stops at station \(2 .\) The distances \(A B, B C\), and \(C D\) are all equal, and it takes 5.00 min to travel between the two stations. Assume that the uniform accelerations have the same magnitude, even when they are opposite in direction. a. How much of this 5.00 min period does the train spend between points \(A\) and \(B ?\) b. How much of this 5.00 min period does the train spend between points \(B\) and \(C ?\) c. How much of this 5.00 min period does the train spend between points \(C\) and \(D ?\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.