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See Sample Problem A. A school bus takes \(0.530 \mathrm{h}\) to reach the school from your house. If the average velocity of the bus is \(19.0 \mathrm{km} / \mathrm{h}\) to the east, what is the displacement?

Short Answer

Expert verified
The displacement of the bus is 10.07 km to the east.

Step by step solution

01

Understand the Problem

The problem is asking for the displacement of the school bus. We are given the average velocity of the bus (19.0 km/h) and the time it takes to reach the school (0.530h). Displacement is the distance covered in a specific direction, it can be found using the formula of velocity which is displacement over time.
02

Plug the values into the formula

The formula to calculate displacement using velocity is displacement = average velocity * time. Plug the values into this formula, i.e., displacement = \(19.0 \, \mathrm{km} / \mathrm{h} * 0.530\, \mathrm{h} \)
03

Calculate the displacement

Calculate the displacement by multiplying the average velocity and time. The result will give us the displacement value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Velocity
Average velocity is a fundamental concept in physics that helps us understand how fast an object moves in a particular direction over a certain period of time. Unlike speed, which is a scalar and only considers magnitude, average velocity is a vector, meaning it also includes direction. This makes it a more comprehensive way to describe motion. To find the average velocity, use the formula:
  • Average velocity = total displacement / total time
The units of average velocity are typically \( ext{distance}/ ext{time} \), such as kilometers per hour (km/h) or meters per second (m/s). In the given problem, the bus has an average velocity of 19.0 km/h to the east, which implies that for each hour of travel, the bus covers 19 kilometers in the eastward direction. Understanding this concept helps to set the context for how far and in what direction the bus actually travels within a given timeframe.
Time Calculation
Time calculation is immensely useful in determining the displacement of an object when certain variables, such as velocity and elapsed time, are known. In our exercise, time is presented directly as 0.530 hours. To work with this time effectively, here are some helpful tips:
  • Ensure that time is consistently expressed in the correct unit that matches the units for velocity.
  • For convenience, you might need to convert time to other units (e.g., from hours to seconds), depending on what is required by the problem.
In our problem, we are already using hours for both the velocity (km/h) and time (h), which makes calculating the displacement straightforward. By plugging the given time and the average velocity into the formula (displacement = average velocity * time), we derive the bus's displacement, a clear demonstration of how time calculation bridges initial data to final results.
Directional Motion
Directional motion signifies movement in a specific direction. Unlike simple distance, which can ignore the direction altogether, displacement explicitly requires knowing the direction of travel. This is why when discussing problems related to velocity and displacement, it is crucial to address direction clearly. The formula for displacement:
  • Displacement = Average velocity * Time
Incorporates direction directly because average velocity includes direction as part of its vector definition. For the school bus example, the motion occurs towards the east, so the displacement is directional in that respect. When solving problems, always make sure the direction is stated or understood, especially when the problem involves vectors. This concept of directional motion aids in accurately computing and understanding the result in spatial terms, ensuring that we do not merely know the distance traveled, but exactly where the object has moved. This makes it especially relevant in navigating and understanding geographical contexts and transport logistics.

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Most popular questions from this chapter

A mountain climber stands at the top of a 50.0 m cliff hanging over a calm pool of water. The climber throws two stones vertically \(1.0 \mathrm{s}\) apart and observes that they cause a single splash when they hit the water. The first stone has an initial velocity of \(+2.0 \mathrm{m} / \mathrm{s}\) a. How long after release of the first stone will the two stones hit the water? b. What is the initial velocity of the second stone when it is thrown? c. What will the velocity of each stone be at the instant both stones hit the water?

A speeder passes a parked police car at \(30.0 \mathrm{m} / \mathrm{s}\) The police car starts from rest with a uniform acceleration of \(2.44 \mathrm{m} / \mathrm{s}^{2}\) a. How much time passes before the speeder is overtaken by the police car? b. How far does the speeder get before being overtaken by the police car?

see Sample Problem \(E\) A sailboat starts from rest and accelerates at a rate of \(0.21 \mathrm{m} / \mathrm{s}^{2}\) over a distance of \(280 \mathrm{m}\) a. Find the magnitude of the boat's final velocity. b. Find the time it takes the boat to travel this distance.

A ranger in a national park is driving at \(56 \mathrm{km} / \mathrm{h}\) when a decr jumps onto the road \(65 \mathrm{m}\) ahead of the vehicle. After a reaction time of \(t\) s, the ranger applies the brakes to produce an acceleration of \(-3.0 \mathrm{m} / \mathrm{s}^{2} .\) What is the maximum reaction time allowed if the ranger is to avoid hitting the deer?

Sketch the velocity-time graphs for the following motions. a. a city bus that is moving with a constant velocity b. a wheelbarrow that is speeding up at a uniform rate of acceleration while moving in the positive direction c. a tiger that is speeding up at a uniform rate of acceleration while moving in the negative direction d. an iguana that is slowing down at a uniform rate of acceleration while moving in the positive direction e. a camel that is slowing down at a uniform rate of acceleration while moving in the negative direction

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