/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 In a desperate attempt to come u... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In a desperate attempt to come up with an equation to solve a problem during an examination, a student tries the following (velocity in \(\mathrm{m} / \mathrm{s}\) ) \(^{2}=\) (acceleration in \(\left.\mathrm{m} / \mathrm{s}^{2}\right) \times(\text { time in } \mathrm{s}\) ). Use dimensional analysis to determine whether this equation might be valid.

Short Answer

Expert verified
The given equation is not valid. This conclusion is based on a dimensional analysis that shows that the dimensions of the quantities on the left-hand side of the equation do not equal the dimensions of the quantities on the right-hand side.

Step by step solution

01

Identify the physical properties involved

The problem provides an equation involving velocity, acceleration, and time. According to the basic definitions of these physical quantities: \n\n- Velocity (V) is displacement per unit time and its dimension is given by [L][T]^-1 where L is the length, and T is time. \n\n- Acceleration (A) is the rate change in velocity per unit time and hence its dimension is [L][T]^-2. \n\n- Time (T) is a basic quantity and its dimension is [T].
02

Conduct dimensional analysis of given equation

Dimensionally analyze the given equation. On the LHS we have Velocity squared whose dimensional formula would be ([L][T]^-1)^2 = [L]^2[T]^-2. \n\nOn the RHS, we have acceleration multiplied by time. Therefore, the dimensional formula would be [L][T]^-2 * [T] = [L][T]^-1.
03

Compare the dimensions on LHS and RHS

Comparing dimensions of LHS and RHS, we find that LHS is [L]^2[T]^-2 and RHS is [L][T]^-1. Since the dimensions on both sides are not equal, we can conclude that the equation is not correct or valid.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity and Acceleration
Understanding the relationship between velocity and acceleration is crucial for students in physics. Velocity describes how quickly an object's position changes over time. In simpler terms, it tells us how fast something is moving and in which direction. For instance, if a car is traveling at a speed of 60 kilometers per hour northwards, this is the car's velocity. It is a vector quantity, which means it has both a magnitude (the speed) and a direction (northwards).

On the other hand, acceleration measures how quickly the velocity changes with time. It can be thought of as the 'speed of the speed'. If the car's speed increases from 60 to 80 kilometers per hour, it is accelerating. Similarly, if it slows down, it is decelerating. Acceleration is also a vector quantity, and it can happen due to an increase or decrease in speed or a change in direction, like when you're turning a corner at a constant speed.

Often, students mix up these concepts, but remembering that velocity is about speed with direction and acceleration is about the change in that speed, can help clarify the differences.
Physical Quantities Dimensions
In physics, understanding the dimensions of physical quantities is a foundational skill. Every physical quantity can be expressed in terms of basic dimensions. This holds true for velocity and acceleration as well. Dimensions provide a mathematical language to discuss the properties of different physical entities and their dependencies.

Take velocity, for instance. As we discussed earlier, it has dimensions of length over time ([L][T]^-1). Length and time are fundamental dimensions represented by 'L' for length and 'T' for time. In the case of acceleration, it's the change in velocity per unit time, which gives it the dimensions of length over time squared ([L][T]^-2).

By learning to work with these dimensions, students can begin to understand how different physical quantities relate to one another. It also serves as a stepping stone towards more complex applications, such as dimensional analysis, which is used to check the validity of physical equations.
Physics Equations Validation
Dimensional analysis is not just about understanding dimensions; it's also a powerful tool for validating the correctness of physics equations. It ensures that each term within an equation is dimensionally consistent with the others. Whenever we encounter an equation or come up with one, like the student in our exercise, we need to ensure that the dimensions match on both sides of the equation.

For the equation in question, velocity^2 = acceleration * time, dimensional analysis helps us deduce its validity. We calculate the dimensions for velocity squared and find they are ([L][T]^-1)^2, which simplifies to [L]^2[T]^-2. For the right-hand side, acceleration times time with dimensions ([L][T]^-2) * [T], simplifies to [L][T]^-1. Since the dimensions don't match up ([L]^2[T]^-2 ≠ [L][T]^-1), we conclude the equation isn't valid.

This method of equation verification is vital for students, as it provides a sanity check before delving into further calculations. It also instills a discipline to approach problems methodically, ensuring that they do not violate fundamental principles of physics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the phrase, "The quick brown fox jumped over the lazy dog." Which details of this situation would a physicist who is modeling the path of a fox ignore?

The radius of the planet Saturn is \(6.03 \times 10^{7} \mathrm{m},\) and its mass is \(5.68 \times 10^{26} \mathrm{kg}\) a. Find the density of Saturn (its mass divided by its volume) in grams per cubic centimeter. (The volume of a sphere is given by \(\frac{4}{3} \pi r^{3}\).) b. Find the surface area of Saturn in square meters. (The surface area of a sphere is given by \(\left.4 \pi r^{2} .\right)\)

Carry out the following arithmetic operations: a. find the sum of the measurements \(756 \mathrm{g}\) $$ 37.2 \mathrm{g}, 0.83 \mathrm{g}, \text { and } 2.5 \mathrm{g} $$ b. find the quotient of \(3.2 \mathrm{m} / 3.563 \mathrm{s}\) c. find the product of \(5.67 \mathrm{mm} \times \pi\) d. find the difference of \(27.54 \mathrm{s}\) and \(3.8 \mathrm{s}\)

A fisherman catches two sturgeons. The smaller of the two has a measured length of \(93.46 \mathrm{cm}\) (two decimal places and four significant figures), and the larger fish has a measured length of \(135.3 \mathrm{cm}\) (one decimal place and four significant figures). What is the total length of the two fish?

Which of the following scenarios fit the approach of he scientific method? a. An auto mechanic listens to how a car runs and comes up with an idea of what might be wrong. The mechanic tests the idea by adjusting the idle speed. Then the mechanic decides his idea was wrong based on this evidence. Finally, the mechanic decides the only other problem could be the fuel pump, and he consults with the shop's other mechanics about his conclusion. b. Because of a difference of opinions about where to take the class trip, the class president holds an election. The majority of the students decide to go to the amusement park instead of to the shore. c. Your school's basketball team has advanced to the regional playoffs. A friend from another school says their team will win because their players want to win more than your school's team does. d. A water fountain does not squirt high enough. The handle on the fountain seems loose, so you try to push the handle in as you turn it. When you do this, the water squirts high enough that you can get a drink. You make sure to tell all your friends how you did it.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.