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Consider steady heat conduction in a plane wall with variable heat generation and constant thermal conductivity. The nodal network of the medium consists of nodes \(0,1,2,3\), and 4 with a uniform nodal spacing of \(\Delta x\). Using the energy balance approach, obtain the finite difference formulation of the boundary nodes for the case of uniform heat flux \(\dot{q}_{0}\) at the left boundary (node 0 ) and convection at the right boundary (node 4) with a convection coefficient of \(h\) and an ambient temperature of \(T_{\infty}\).

Short Answer

Expert verified
Answer: The finite difference formulations for the boundary nodes are as follows: 1. For node 0: \(T_0 = T_1 - \frac{\Delta x}{k} \cdot \dot{q}_0\) 2. For node 4: \(T_4 = \left(\frac{\Delta x}{k} \cdot h + \Delta x \cdot \frac{1}{k}\right) T_{3} - \Delta x \cdot \frac{1}{k} \cdot T_{\infty}\)

Step by step solution

01

Write energy balance equation for node 0

Write the energy balance equation for node 0: $$\dot{q}_0 - k \frac{T_1 - T_0}{\Delta x} = 0$$ Rearrange this equation to obtain the finite difference formulation for node 0: $$T_0 = T_1 - \frac{\Delta x}{k} \cdot \dot{q}_0$$
02

Write energy balance equation for node 4

Write the energy balance equation for node 4: $$k \frac{T_{3} - T_{4}}{\Delta x} - h \cdot (T_{4} - T_{\infty}) = 0$$ Rearrange this equation to obtain the finite difference formulation for node 4: $$T_4 = \left(\frac{\Delta x}{k} \cdot h + \Delta x \cdot \frac{1}{k}\right) T_{3} - \Delta x \cdot \frac{1}{k} \cdot T_{\infty}$$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Conduction
Heat conduction is a process that describes how thermal energy moves within a material due to a temperature difference. In simple terms, it is the transfer of heat from a hot region to a cooler one. Conduction happens mainly through collisions between atoms and molecules, and also through the movement of electrons in a solid. In the context of a plane wall, as given in the problem, conduction involves analyzing how heat moves through the wall material.

When we speak about steady heat conduction, it means that the temperature distribution within the material does not change with time. The system has reached a state of thermal equilibrium. This is crucial because it simplifies the analysis, eliminating time-dependent terms, and allowing us to use straightforward methods like the finite difference approach.

In this method, the wall is subdivided into nodes or small sections, and the temperature at each node is calculated based on the temperatures of its neighboring nodes. The finite difference method is particularly useful for problems with complex boundaries or variable material properties.
Energy Balance Equation
The energy balance equation is a mathematical expression of the conservation of energy principle applied to a specific point in a system, such as a node on a wall. It represents the idea that the amount of energy entering or leaving a control volume must equal the change in energy stored in that volume.

For a node on a wall in heat conduction analysis, the energy balance can be expressed in terms of heat input, heat conducted into the node, and heat change due to temperature differences. For example, at node 0 on the left boundary, the energy balance is initially written as:
  • \( \dot{q}_0 - k \frac{T_1 - T_0}{\Delta x} = 0 \)
Here:
  • \( \dot{q}_0 \): is the heat flux entering at node 0
  • \( k \frac{T_1 - T_0}{\Delta x} \): is the heat conducted between nodes 0 and 1
This balance ensures that all the energy flowing into and out of a node is accounted for, leading to accurate temperature predictions at each node level.
Boundary Conditions
Boundary conditions are crucial in the accurate analysis of heat conduction problems as they define how the system interacts with its surroundings. They are the known values or expressions applied at the boundaries of the domain where the heat conduction is being analyzed.

In the exercise, we have two types of boundary conditions:
  • **Left Boundary Condition (Uniform Heat Flux):** At node 0, the boundary condition specifies a known and steady uniform heat flow into the surface \( \dot{q}_0 \). This is represented in the energy balance equation and influences how the finite difference expression is set up for the temperature at node 0.


  • **Right Boundary Condition (Convection):** At node 4, convection is the mode of heat transfer. Here, heat is lost from the wall surface to the surrounding fluid. The convection at this boundary is modeled using the convection coefficient \( h \) and the ambient temperature \( T_\infty \). This information is used to construct the energy balance at node 4:
  • \( k \frac{T_3 - T_4}{\Delta x} - h \cdot (T_4 - T_\infty) = 0 \)
These boundary conditions help determine how heat enters and leaves the system, which is pivotal for solving the conduction problem accurately using the finite difference method.

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Most popular questions from this chapter

How is an insulated boundary handled in finite difference formulation of a problem? How does a symmetry line differ from an insulated boundary in the finite difference formulation?

Consider transient one-dimensional heat conduction in a plane wall that is to be solved by the explicit method. If both sides of the wall are subjected to specified heat flux, express the stability criterion for this problem in its simplest form.

Consider a medium in which the finite difference formulation of a general interior node is given in its simplest form as $$ T_{\text {node }}=\left(T_{\text {left }}+T_{\text {top }}+T_{\text {right }}+T_{\text {bottom }}\right) / 4 $$ (a) Is heat transfer in this medium steady or transient? (b) Is heat transfer one-, two-, or three-dimensional? (c) Is there heat generation in the medium? (d) Is the nodal spacing constant or variable? (e) Is the thermal conductivity of the medium constant or variable?

Express the general stability criterion for the explicit method of solution of transient heat conduction problems.

A common annoyance in cars in winter months is the formation of fog on the glass surfaces that blocks the view. A practical way of solving this problem is to blow hot air or to attach electric resistance heaters to the inner surfaces. Consider the rear window of a car that consists of a \(0.4\)-cm-thick glass \(\left(k=0.84 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\right.\) and \(\left.\alpha=0.39 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)\). Strip heater wires of negligible thickness are attached to the inner surface of the glass, \(4 \mathrm{~cm}\) apart. Each wire generates heat at a rate of \(25 \mathrm{~W} / \mathrm{m}\) length. Initially the entire car, including its windows, is at the outdoor temperature of \(T_{o}=-3^{\circ} \mathrm{C}\). The heat transfer coefficients at the inner and outer surfaces of the glass can be taken to be \(h_{i}=6\) and \(h_{o}=20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. Using the explicit finite difference method with a mesh size of \(\Delta x=\) \(0.2 \mathrm{~cm}\) along the thickness and \(\Delta y=1 \mathrm{~cm}\) in the direction normal to the heater wires, determine the temperature distribution throughout the glass \(15 \mathrm{~min}\) after the strip heaters are turned on. Also, determine the temperature distribution when steady conditions are reached.

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