/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 116 A common annoyance in cars in wi... [FREE SOLUTION] | 91影视

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A common annoyance in cars in winter months is the formation of fog on the glass surfaces that blocks the view. A practical way of solving this problem is to blow hot air or to attach electric resistance heaters to the inner surfaces. Consider the rear window of a car that consists of a \(0.4\)-cm-thick glass \(\left(k=0.84 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\right.\) and \(\left.\alpha=0.39 \times 10^{-6} \mathrm{~m}^{2} / \mathrm{s}\right)\). Strip heater wires of negligible thickness are attached to the inner surface of the glass, \(4 \mathrm{~cm}\) apart. Each wire generates heat at a rate of \(25 \mathrm{~W} / \mathrm{m}\) length. Initially the entire car, including its windows, is at the outdoor temperature of \(T_{o}=-3^{\circ} \mathrm{C}\). The heat transfer coefficients at the inner and outer surfaces of the glass can be taken to be \(h_{i}=6\) and \(h_{o}=20 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\), respectively. Using the explicit finite difference method with a mesh size of \(\Delta x=\) \(0.2 \mathrm{~cm}\) along the thickness and \(\Delta y=1 \mathrm{~cm}\) in the direction normal to the heater wires, determine the temperature distribution throughout the glass \(15 \mathrm{~min}\) after the strip heaters are turned on. Also, determine the temperature distribution when steady conditions are reached.

Short Answer

Expert verified
Answer: The key steps are: 1. Calculate the explicit stability criterion and choose an appropriate time step. 2. Initialize the temperature grid with the outdoor temperature and given mesh size. 3. Apply boundary conditions at the inner and outer surfaces of the glass. 4. Update the interior nodes using the explicit finite difference method for each time step. 5. Calculate the steady-state temperature distribution by running the simulation until the temperature changes become smaller than a given tolerance.

Step by step solution

01

Calculate Explicit Stability Criterion

We need to determine if the explicit finite difference method is stable for this problem. This is done by calculating the Fourier number (Fo) using the explicit stability criterion formula: Fo = \(\alpha \cdot \frac{螖t}{(螖x)^2}\) Where 伪 (alpha) is the thermal diffusivity, 螖t is the time step, and 螖x is the mesh size in the x-direction. The criterion for stability is that Fo must be less than or equal to 1/2. Using the given 螖x = 0.2 cm and 伪 = 0.39脳10鈦烩伓 m虏/s, we can determine the maximum 螖t that will result in a stable solution.
02

Choose Time Step and Initialize Temperature Grid

Once we determine the maximum 螖t for stability, we can choose a time step for our analysis. It is usually a good idea to choose a time step slightly smaller than the maximum to ensure stability. Next, we'll create a grid to represent the temperature values at each mesh point. Since our mesh size is 螖x = 0.2 cm and 螖y = 1 cm, we can determine the dimensions of the grid. The initial temperature of the entire grid will be set equal to the outdoor temperature (\(T_o\)) of -3掳C.
03

Apply Boundary Conditions

Now, we need to apply boundary conditions at the inner and outer surfaces of the glass. The heat transfer coefficients are provided for both surfaces: \(h_i = 6\) W/m虏K at the inner surface and \(h_o = 20\) W/m虏K at the outer surface. The heat flux at each surface can be calculated using the heat transfer coefficient at that surface, and the temperature difference between the surface and the adjacent nodes will be calculated. We can then update the corresponding boundary nodes using the calculated heat fluxes.
04

Update Interior Nodes Using Explicit Finite Difference Method

With the boundary conditions applied, we can now update the temperatures at the interior nodes using the explicit finite difference method. The temperature at each interior node can be updated using the neighboring temperatures and the thermal conductivity (k) of the glass: \(T_i^{new} = T_i^{old} + k \cdot \frac{螖t}{(螖x)^2} \cdot (T_{i+1}^{old} - 2T_i^{old} + T_{i-1}^{old})\) We'll perform these calculations iteratively for each time step until the total simulation time (in our case, 15 minutes) is reached.
05

Calculate Steady-State Temperature Distribution

After 15 minutes have passed, we can calculate the steady-state temperature distribution by running the simulation until the temperature change between time steps for each mesh point is much smaller than a given tolerance (for example, 0.01掳C). Once the steady-state temperature distribution has been reached, we can analyze the temperature distribution across the glass.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Transfer
Heat transfer is a fundamental concept in physics that describes how thermal energy moves from one point to another. In our scenario, the focus is on the process of preventing fogging on a car's rear window by heating it.
This heating process involves transferring heat from heater wires to the glass surface. Understanding how heat moves is key to figuring out how quickly and evenly the temperature will change across the window.
There are three main modes of heat transfer:
  • **Conduction**: Direct transfer of heat through a material, like the heat flowing through the glass.
  • **Convection**: Transfer of heat by the movement of fluids or gases, such as the hot air blown against the window surfaces.
  • **Radiation**: Transfer of heat in the form of electromagnetic waves that doesn't require a medium.
In this specific problem, conduction through glass and convective heat transfer from the air to the glass surface are the primary mechanisms at work. Knowing these processes helps facilitate designing systems that provide efficient heating, avoiding fog with minimal energy use.
Thermal Conductivity
Thermal conductivity is a material property that quantifies how well it can conduct heat. It's represented by the symbol \(k\) and measured in units of \( ext{W/m} \, \cdot \text{K}\) (watts per meter per Kelvin). In simpler terms, it describes how easily heat can travel through a material.
In the case of the glass window, the given thermal conductivity is \(0.84 \, \text{W/m} \, \cdot \text{K}\), indicating that glass is moderately conductive. This affects how quickly the glass can heat up and distribute the heat generated by the heater wires.
Higher thermal conductivity implies faster heat transfer through the material. For instance, metals typically have high thermal conductivity. In contrast, materials like wood or rubber are poor conductors, being better insulators. Understanding these properties is crucial for designing effective heating elements and systems.
Stability Criterion
When using numerical methods like the finite difference method to solve heat transfer problems, ensuring stability is crucial. Stability ensures that the numerical solution behaves and converges correctly, providing accurate results.
In this problem, the stability criterion is addressed by calculating the Fourier number \(\text{Fo}\). It is defined in the finite difference method as:\[\text{Fo} = \alpha \cdot \frac{\Delta t}{(\Delta x)^2}\]where:
  • \(\alpha\) is the thermal diffusivity of the material.
  • \(\Delta t\) is the time step size.
  • \(\Delta x\) is the size of the spatial step.
For stability in an explicit finite difference method, \(\text{Fo}\) must be less than or equal to \(\frac{1}{2}\). This ensures that the temperature updates at each step do not "explode" and lead to unrealistic values.
This calculation helps determine appropriate time steps for simulations, ensuring accurate modeling of the heat transfer over time.
Temperature Distribution
Temperature distribution refers to how temperatures vary throughout the material, in this case, the glass window over time and space.
By simulating with the finite difference method, we can understand how heat moves from the heater wires through the glass. The initial state has the glass at a uniform temperature of \(-3^{\circ} \text{C}\). Over time, as the heater wires transfer heat, the temperature within the glass changes.
The goal is to determine two main temperature distributions:
  • **Transient Distribution**: The temperature profile at a specific time, such as 15 minutes after the heater activation.
  • **Steady-State Distribution**: The temperature profile once equilibrium has been reached, with no further changes over time.
Accurate knowledge of these distributions is essential for assessing how efficiently the window defogs and ensures a clear view. It also informs designs to optimize heating and energy usage.

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Most popular questions from this chapter

The unsteady forward-difference heat conduction for a constant area, \(A\), pin fin with perimeter, \(p\), exposed to air whose temperature is \(T_{0}\) with a convection heat transfer coefficient of \(h\) is $$ \begin{aligned} T_{m}^{*+1}=& \frac{k}{\rho c_{p} \Delta x^{2}}\left[T_{m-1}^{*}+T_{m+1}^{*}+\frac{h p \Delta x^{2}}{A} T_{0}\right] \\\ &-\left[1-\frac{2 k}{\rho c_{p} \Delta x^{2}}-\frac{h p}{\rho c_{p} A}\right] T_{m}^{*} \end{aligned} $$ In order for this equation to produce a stable solution, the quantity \(\frac{2 k}{\rho c_{p} \Delta x^{2}}+\frac{h p}{\rho c_{p} A}\) must be (a) negative (b) zero (c) positive (d) greater than 1 (e) less than 1

Consider a large uranium plate of thickness \(5 \mathrm{~cm}\) and thermal conductivity \(k=28 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}\) in which heat is generated uniformly at a constant rate of \(\dot{e}=6 \times 10^{5} \mathrm{~W} / \mathrm{m}^{3}\). One side of the plate is insulated while the other side is subjected to convection to an environment at \(30^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(h=60 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). Considering six equally spaced nodes with a nodal spacing of \(1 \mathrm{~cm},(a)\) obtain the finite difference formulation of this problem and \((b)\) determine the nodal temperatures under steady conditions by solving those equations.

Consider steady heat conduction in a plane wall whose left surface (node 0 ) is maintained at \(30^{\circ} \mathrm{C}\) while the right surface (node 8 ) is subjected to a heat flux of \(1200 \mathrm{~W} / \mathrm{m}^{2}\). Express the finite difference formulation of the boundary nodes 0 and 8 for the case of no heat generation. Also obtain the finite difference formulation for the rate of heat transfer at the left boundary.

Design a fire-resistant safety box whose outer dimensions are \(0.5 \mathrm{~m} \times 0.5 \mathrm{~m} \times 0.5 \mathrm{~m}\) that will protect its combustible contents from fire which may last up to \(2 \mathrm{~h}\). Assume the box will be exposed to an environment at an average temperature of \(700^{\circ} \mathrm{C}\) with a combined heat transfer coefficient of \(70 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) and the temperature inside the box must be below \(150^{\circ} \mathrm{C}\) at the end of \(2 \mathrm{~h}\). The cavity of the box must be as large as possible while meeting the design constraints, and the insulation material selected must withstand the high temperatures to which it will be exposed. Cost, durability, and strength are also important considerations in the selection of insulation materials.

Two 3-m-long and 0.4-cm-thick cast iron \((k=\) \(52 \mathrm{~W} / \mathrm{m} \cdot \mathrm{K}, \varepsilon=0.8)\) steam pipes of outer diameter \(10 \mathrm{~cm}\) are connected to each other through two \(1-\mathrm{cm}\)-thick flanges of outer diameter \(20 \mathrm{~cm}\). The steam flows inside the pipe at an average temperature of \(200^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(180 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\). The outer surface of the pipe is exposed to convection with ambient air at \(8^{\circ} \mathrm{C}\) with a heat transfer coefficient of \(25 \mathrm{~W} / \mathrm{m}^{2} \cdot \mathrm{K}\) as well as radiation with the surrounding surfaces at an average temperature of \(T_{\text {surr }}=290 \mathrm{~K}\). Assuming steady one-dimensional heat conduction along the flanges and taking the nodal spacing to be \(1 \mathrm{~cm}\) along the flange \((a)\) obtain the finite difference formulation for all nodes, \((b)\) determine the temperature at the tip of the flange by solving those equations, and \((c)\) determine the rate of heat transfer from the exposed surfaces of the flange.

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